我實現了adresbook和adress類!我想實現一個方法「searchForename」和「searchSurename」,這是我之前用「insert」添加的搜索元素。我用ArrayList來查看其他實現,它搜索對象或元素,但大多數情況下他們真的讓我感到困惑,因爲太多的代碼沒有任何解釋。包含新的問題!:在ArrayList中實現toString方法和構造函數
第三編輯
第三次嘗試:
import java.util.ArrayList;
public class Adressbook {
private ArrayList<Adress> adresses = null;
public Adressbook(){
adresses = new ArrayList<Adress>();
}
public void insert(Adress adress){
adresses.add(new Adress("Marvin","Wildman","Blastreet",9,12345,"Blatown"));
adresses.add(new Adress("Anne","Wildman","Woodstreet",10,6789,"Exampletown"));
adresses.add(new Adress("William","Wildman","Eaglestreet",11,73975,"Blubvalley"));
}
public void searchSurename(String surename){
for(Adress s: adresses){
if("Green".equals(surename)){
System.out.println(s);
}
}
}
public void searchForename(String forename){
for(Adress s: adresses){
if("Anne".equals(forename)){
System.out.println(s);
}
}
}
public String toString(){
return null;
}
}
我有幾個問題:
1.How並在Adressbook toString方法是什麼樣子?
2.Adress類的toString如何看起來像?
3.構造函數在Adress類中看起來是否正確?
4.可以實現比這更簡單/更高效的搜索方法嗎?如果不正確,我該如何改變它?
忘記我的課地址:
public class Adress {
public static String forename;
public static String surename;
public static String street;
public static int houseno;
public static int code;
public static String state;
public Adress(String forename, String surename, String street, int houseno, int code,String state){
this.forename = forename;
this.surename = surename;
this.street = street;
this.houseno = houseno;
this.code = code;
this.state = state;
}
public String toString(){
return null;
}
}
瞭解[我如何在Java中比較字符串(http://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java) –
謝謝!我是這個主題的新手。我有很多要學習的。 –
在附註地址是拼寫地址。變量名稱中的錯字最好避免。 –