如何比較兩個的DateTimePicker值在C＃

Question

我有一個Windows Form應用程序，它有兩個DateTimePicker控件顯示和「DATE加盟」「出生日期」的問題。

我想比較這些控件的值，使得出生日期應不小於且不大於，不應該等於小於且不大於不應該是平等的......

我該怎麼做？

Answer 1

正如jbutler483

建議我試圖這樣做，但我不能最後得到任何解決方案，我自己的知識我用以下代碼

private void dtpdob_ValueChanged(object sender, EventArgs e) 
    { 
     int year = DateTime.Today.Year - dtpdob.Value.Year; 
     int month = DateTime.Today.Month - dtpdob.Value.Month; 
     int day = DateTime.Today.Day - dtpdob.Value.Day; 
     var a = year.ToString(); 
     var b = month.ToString(); 
     var c = day.ToString(); 
     if (day != 0 && month!=0 && year!=0) 
     { 
      if(day!=1) 
      txtage.Text = a + " Years " + b + " Months " + c + " Days "; 
      else 
       txtage.Text = a + " Years " + b + " Months " + c + " Day "; 
     } 
     else if (day == 0 && month == 0) 
      txtage.Text = a + " Years "; 
     else if (day == 0 && month != 0) 
      txtage.Text = a + " Years " + b + " Months "; 
     else 
      txtage.Text = a + " Years " + b + " Months " + c + " Days "; 
    } 

Answer 2

試試這個代碼

DateTimePicker dtBDay = new DateTimePicker(); 
dtBDay.Value = DateTime.Now.AddYears(-5); 
DateTimePicker dtJoin = new DateTimePicker(); 
dtJoin.Value = DateTime.Now; 
if (dtBDay.Value >= dtJoin.Value) 
{ 
    throw new Exception("Date of Join cannot be less than or equal to Date of Birth"); 
} 

希望這將有助於