從數據列

Question

分隔值我有一個像

I~A~G~S 

我怎麼可以使用select查詢它們分開與數據的列。

輸出： 更新

Rows  Column(Data) 
    First  I 
    Second  A 
    Third  G 
    Fourth  S 

Answer 1

如果喲ü正在使用Oracle數據庫，那麼它應該是如下：

select replace('I~A~G~S','~',' ') as x from dual; 

select replace(<fieldname>,'~',' ') from <tablename> 

爲不同行分割字符串，請檢查下面的查詢問題。

SELECT trim(regexp_substr(replace('I~A~G~S','~',','), '[^,]+', 1, LEVEL)) str_2_tab 
    FROM dual 
    CONNECT BY LEVEL <= regexp_count(replace('I~A~G~S','~',','), ',')+1; 

Answer 2

declare @s varchar(10) 
set @s='I~A~G~S' 

select replace(@s,'~',' ') 

爲updated question

create table #vij11 (s varchar(100)) 

insert into #vij11(s) values ('I~A~G~S') 
SELECT 
    Split.a.value('.', 'VARCHAR(100)') AS String 
FROM (SELECT [s], 
     CAST ('<M>' + REPLACE([s], '~', '</M><M>') + '</M>' AS XML) AS String 
    FROM #vij11) AS A CROSS APPLY String.nodes ('/M') AS Split(a); 

fiddle demo