drop table if exists sailors;
drop table if exists reserves;
create table sailors(sid int, sname varchar(3));
create table reserves(bid int,sid int, dt date);
insert into sailors values
(1,'abc'),(2,'def'),(3,'ghi');
insert into reserves values
(100,1,'2017-01-01'),(200,1,'2017-01-01'),
(100,1,'2017-01-02'),(100,1,'2017-01-02'),
(100,2,'2017-01-01'),(100,2,'2017-01-01'),(300,2,'2017-01-01'),
(100,2,'2017-01-03'),(200,2,'2017-01-04')
;
select s.sid,t.sname,s.dt
,group_concat(s.bid order by s.bid) boats
from
(
select r.sid,r.dt,r.bid,
if(concat(r.sid,r.dt,r.bid) <> @p, @rn:=1,@rn:[email protected]+1) rn,
@p:=concat(r.sid,r.dt,r.bid) p
from (select @rn:=0,@p:='') rn,reserves r
order by r.sid,r.dt,r.bid
) s
join sailors t on t.sid = s.sid
where s.rn = 1
group by s.sid,s.dt
having instr(boats,',') > 0
+------+-------+------------+---------+
| sid | sname | dt | boats |
+------+-------+------------+---------+
| 1 | abc | 2017-01-01 | 100,200 |
| 2 | def | 2017-01-01 | 100,300 |
+------+-------+------------+---------+
2 rows in set (0.00 sec)
你的兩個表的模型描述是不完整的錯過。此外,加入r1和r2的查詢可能應該加入'... AND R1.bid> R2.bid',以避免在無序元組上重複。 – Sebas
@ Sebas我應該提供表格的實例嗎? – Barry
我的意思是,你的定義中似乎有些列缺失(例如儲備中的日子列)。我想我們需要他們加入的目的,否則我不明白你怎麼可以加入水手和儲備一起 – Sebas