創建與值的字典作爲另一個列表

Question

我有如下一些數據：

United Kingdom,57533000,London,6756000,Europe,1066,1945,-,English 
United States,252177000,Washington DC,606900,North America,1776,1945,-,English 
Venezuela,19733000,Caracas,1290087,Latin America,1811,1945,-,Spanish 
Vietnam,67589000,Hanoi,1088862,Orient,1945,1977,-,Vietnamese 
Yemen,1184300,San'a,427150,Asia,1918,1957,Islam,Arabic 
Argentina,36955182,Buenos Aires,2033445,Latin America,1853,1945,-,Spanish 
Brazil,172860370,Brasilia,286037,0Latin America,1822,1945,-,Portuguese 
Bahrain,634137,Manama,34137,Persian Gulf,1973,1977,Islamic,Arabic 
Cameroon,15421937,Yaounde,421937,Africa,1960,1974,-,Franch 
Djibouti,451442,Djibouti,1442,Africa,1977,1980,-,Franch 
Equatorial Guinea,474214,Malabo,74214,Africa,1991,1995,-,Franch 
Fiji,832494,Suva,32494,Oceania,1970,1975,-,English 
France,59329691,Paris,329691,Europe,486,1945,-,Franch 
Greece,10601527,Athens,601527,Europe,1829,1945,-,Greek 
Germany,82797408,Berlin,1797408,Europe,1871,1960,-,German 
Honduras,6249598,Tegucigalpa,1249598,Latin America,1821,1945,-,Spanish 
China,1261832482,Beijing,61832482,Asia,-221,1945,-,Chinese 
Canada,31281092,Ottawa,1281092,North America,1867,1945,-,English 
Hungary,10138844,Budapest,1138844,Europe,1001,1945,-,Hungerian 
India,1014003817,New Delhi,14003817,Asia,1947,1950,-,Indian 
Italy,57634327,Rome,3634327,Europe,1861,1950,-,Italian 
Ireland,3797257,Dublin,797257,Europe,1921,1945,-,English 
Japan,126549976,Tokio,16549976,Asia,-660,1955,-,Japanese 

我的要求是將數據存儲在字典如下：

{'Portuguese': ['Brazil'], 'Franch': ['Cameroon', 'Djibouti', 'Equatorial Guinea', 'France'], 'Chinese': ['China'], 'Vietnamese': ['Vietnam'], 'German': ['Germany'], 'English': ['United Kingdom', 'United States', 'Fiji', 'Canada', 'Ireland'], 'Japanese': ['Japan'], 'Greek': ['Greece'], 'Indian': ['India'], 'Spanish': ['Venezuela', 'Argentina', 'Honduras'], 'Arabic': ['Yemen', 'Bahrain'], 'Hungerian': ['Hungary'], 'Italian': ['Italy']} 

有人可以幫我實現這個？

張貼爲重複的其他查詢不幫助我。我添加了我試過的代碼。請幫幫我。

Answer 1

對您的問題有很多評論，要求您發佈代碼格式正確的問題本身。這肯定會讓你早日得到答覆。

我把你粘貼爲註釋的代碼，並試圖對其進行格式化，我想出了這個：

countryData=open('filename.txt','r') 
dictCountry={} 
langList=[] 
countryList=[] 

def createList(langL,input): 
    input=input.rstrip() 
    country=input.split(',')[0] 
    if input.split(',')[-1] in langL: 
     countryList.append(country) 
    return countryList 

for line1 in countryData: 
    line1=line1.rstrip() 
    lang1=line1.split(',')[-1] 
    if lang1 not in langList: 
     langList.append(lang1) 

for line2 in countryData: 
    line2=line2.rstrip() 
    lang=line2.split(',')[-1] 
    dictCountry[lang]=createList(lang, line2) 

print(dictCountry) 

沒有與您嘗試的幾個問題：

• 迭代多時間在同一個打開的文件上。這將使第二for循環永遠不會運行
• countryList是全局定義的，所以
• 一旦langList內容填充，它從來沒有使用過它從來都保不住只是當前語言的國家

我改變了它一點點的工作液：

f = open('filename.txt','r') 
countryData = f.readlines() 
f.close() 

dictCountry = {} 

for line in countryData: 
    line = line.rstrip() 
    lang = line.split(',')[-1] 
    country = line.split(',')[0] 
    if lang not in dictCountry: 
     dictCountry[lang] = [] 

    dictCountry[lang].append(country) 

print(dictCountry) 

Answer 2

希望下面給出的解決方案將幫助out.I我還附上輸出什麼，我得到：

 f = open('lang.txt','r') 
     countryData = f.readlines() //reading all contents of file 
     f.close() 

     dictCountry = {} 

     for line in countryData: 
      pos = 0 

      line = line.rstrip() 
      lang = line.split(',')[-1] //getting the lang name from eachline 
      #updating the list of languages 
      if lang not in dictCountry: 
       dictCountry[lang] = [] 

      country = line.split(',') //splitting the line fro country names 
      sub = ' ' 
      for i in country: 
       if i in dictCountry.keys(): //ignoring lang name present in 
        pass 
       elif i.isalpha(): 
        dictCountry[lang].append(i) 
       elif i.find(sub)!= -1: 
        dictCountry[lang].append(i) 
       else: 
        pass 

     for i in dictCountry.keys(): 
      print i," : ",dictCountry[i] 


**Output : 
Portuguese : ['Brazil', 'Brasilia', '0Latin America'] 
Franch : ['Cameroon', 'Yaounde', 'Africa', 'Djibouti', 'Djibouti', 'Africa', 'Equatorial Guinea', 'Malabo', 'Africa', 'France', 'Paris', 'Europe'] 
Chinese : ['China', 'Beijing', 'Asia'] 
Vietnamese : ['Vietnam', 'Hanoi', 'Orient'] 
German : ['Germany', 'Berlin', 'Europe'] 
English : ['United Kingdom', 'London', 'Europe', 'United States', 'Washington DC', 'North America', 'Fiji', 'Suva', 'Oceania', 'Canada', 'Ottawa', 'North America', 'Ireland', 'Dublin', 'Europe'] 
Japanese : ['Japan', 'Tokio', 'Asia'] 
Greek : ['Greece', 'Athens', 'Europe'] 
Indian : ['India', 'New Delhi', 'Asia'] 
Spanish : ['Venezuela', 'Caracas', 'Latin America', 'Argentina', 'Buenos Aires', 'Latin America', 'Honduras', 'Tegucigalpa', 'Latin America'] 
Arabic : ['Yemen', 'Asia', 'Islam', 'Bahrain', 'Manama', 'Persian Gulf', 'Islamic'] 
Hungerian : ['Hungary', 'Budapest', 'Europe'] 
Italian : ['Italy', 'Rome', 'Europe']** 

Answer 3

Here is the answer I could reach to: 

f=open('country.txt','r') 
countryData1=f.readlines() 
f.close() 

sourceDict={} 
destDict={} 

for lines in countryData1: 
    lines=lines.rstrip() 
    lang=lines.split(',')[-1] 
    if lang not in sourceDict.keys(): 
     sourceDict[lang]=lines.split(',')[0]+"," 
    else: 
     sourceDict[lang]+=lines.split(',')[0]+","  

for item in sourceDict.keys(): 
    sourceDict[item]=str(sourceDict[item]).rstrip(',') 
    destDict[item]=str(sourceDict[item]).split(',') 


for item in destDict.keys(): 
    print(item+ " "+ str(destDict[item]))