如何把存儲過程作業睡眠持續35分鐘

Question

我下面有一段代碼，下面是基於有視圖的某些條件清理表的存儲過程，如果它被刷新，現在請告知，如果我們需要把邏輯循環。如果清理不發生，就應該睡15分鐘，然後重新嘗試，請告知如何做到這一點

create or replace procedure table_clean_up 
is 
    v_refresh_date date; 
    v_table_count_m integer; 
    v_table_count_p integer; 

begin 
    select count(*) into v_table_count_m 
    from all_mviews 
    where owner = 'M_TO' 
    and mview_name in ('DC_CASHFLOW_VIEW','DC_CASHFLOW_VIEW_ZERO') 
    and last_refresh_type = 'COMPLETE'; 

    if v_table_count_m = 2 then 
     select cast(last_start_date as date) into v_refresh_date 
     from user_scheduler_jobs 
     where job_name = 'TABLE_CLEAN_UP_JOB'; 

     select count(*) into v_table_count_p 
     from all_mviews m 
     where m.owner = 'P_SM_TO' 
     and m.mview_name in ('DC_CASHFLOW_VIEW', 'DC_CASHFLOW_VIEW_ZERO') 
     and m.last_refresh_type = 'COMPLETE' 
     and m.last_refresh_date > v_refresh_date; 

     if v_table_count_p = 2 then 
      delete dc_cashflow_delta; 
     end if; 
    end if; 

末;

Answer 1

... 
DBMS_LOCK.SLEEP(60*35); 
...