麻煩鏈接到一個MySQL表

Question

我有這樣一段代碼：

<?php 
include('base.php'); 
?> 

<?php 
if(isset($_GET['MomentEvent'])) 
{ 
    $MomentEvent = intval($_GET['MomentEvent']); 
    $dn = mysql_query('select TitreEvent, DescriptionEvent from users_event where MomentEvent="'.$MomentEvent.'"'); 
    if(mysql_num_rows($dn)>0) 
    { 
      $dnn = mysql_fetch_array($dn); 
      ?> 

我的問題是鏈接到users_event表從未和：

«對不起TitreEvent未找到»

消息總是彈出在我的臉上。我究竟做錯了什麼？

編輯：完整的代碼

<?php 
include('base.php'); 
?> 

<?php 
if(isset($_GET['MomentEvent'])) 
{ 
    $MomentEvent = intval($_GET['MomentEvent']); 
    $dn = mysql_query('select TitreEvent, DescriptionEvent from users_event where MomentEvent="'.$MomentEvent.'"'); 
    if(mysql_num_rows($dn)>0) 
    { 
      $dnn = mysql_fetch_array($dn); 

?> 
This is the profile of "<?php echo htmlentities($dnn['TitreEvent']); ?>" : 
<table style="width:500px;"> 
    <tr> 
    <td><?php 
if($dnn['avatar']!='') 
{ 
    echo '<img src="'.htmlentities($dnn['avatar'], ENT_QUOTES, 'UTF-8').'" alt="Avatar"  style="max-width:100px;max-height:100px;" />'; 
} 
else 
{ 
    echo 'This user dont have an avatar.'; 
} 
?></td> 
    <td class="left"><h1><?php echo htmlentities($dnn['TitreEvent'], ENT_QUOTES, 'UTF-8'); ? ></h1> 
     Email: <?php echo htmlentities($dnn['DescriptionEvent'], ENT_QUOTES, 'UTF-8'); ?><br /> 
     </tr> 
</table> 
<?php 
    } 
    else 
    { 
      echo 'Sorry TitreEvent not found'; 
    } 
} 
else 
{ 
    echo 'The user ID is not defined.'; 
} 
?> 
         </body> 
</html> 

Answer 1

你有引號混合和匹配的方式太多了。試試這個

$dn = mysql_query("select TitreEvent, DescriptionEvent from users_event where MomentEvent=$MomentEvent ");