在MySQL

Question

選擇不同的列字段和總金額爲它，我有如下表：

topic_id(unique) forum_id forum_views 

1002    1885   5 
1003    1893   2 
1004    1885   3 
1005    1892   6 

我怎樣才能產出這樣的：

forum_id forum_views 
1885   8 
1893   2 
1892   6 

（從上表總論壇觀點獨特forum_id）

任何幫助感謝。

這就是我努力：

從table_name的選擇不同forum_id，SUM（topic_views）

Answer 1

select forum_id, 
     sum(forum_views) as forum_views 
from jforum_topics 
group by forum_id 

Answer 2

你只需要一個GROUP BY指定了哪些行你希望SUM應用於;

select forum_id, sum(topic_views) from jforum_topics 
group by forum_id 
order by forum_id 

Answer 3

試試這個：

select forum_id, sum(topic_views) 
from jforum_topics 
group by forum_id 

Answer 4

select forum_id, sum(topic_views) from jforum_topics group by forum_id 

Answer 5

select forum_id, sum(forum_views) as sum from table_name group by forum_id 

Answer 6

試試這個，這將總結您就到forum_id forum_views。

SELECT forum_id 
    , SUM(forum_views) 
FROM TABLE_NAME 
GROUP BY forum_id 
ORDER BY 1 

Answer 7

這將是

select id2,sum(id3) from supportContacts group by id2 

看到這個SQL小提琴http://sqlfiddle.com/#!2/7b9e7/3

Answer 8

使用此查詢select forum_id, sum(distinct forum_views) from table group by forum_id;

在此查詢和不同會做不同的價值的總和，做按期望的列進行分組。

如果你想不管清晰度的所有值的總和，那麼只需使用sum(forum_views)。

Answer 9

你也可以試用一下：

select distinct forum_id, sum(topic_views) 
from jforum_topics 
group by forum_id