XMPP房間邀請朋友IOS

我在ios中使用XMPP框架。我如何邀請其他用戶進行羣聊？XMPP房間邀請朋友IOS

[xmppRoom1 inviteUser:[XMPPJID jidWithString:@"[email protected]"] withMessage:@"Come Join me"];

來源

2013-11-22 Aamer Khalid

您可以MUC邀請多個用戶逐一：

for (int contactIndex = 0; contactIndex <contactsToInviteArray.count; contactIndex++) 
{ 
    NSString * inviteUserJID = [NSString stringWithFormat:@"%@@%@",[contactsToInviteArray enter code hereobjectAtIndex:contactIndex], SERVER_NAME]; 
    [xmppRoom1 inviteUser:[XMPPJID jidWithString:inviteUserJID] withMessage:@"Come Join me"]; 

}

來源

2014-09-25 09:28:53

在調用invite函數之前，我們是否需要執行此代碼？ _xmppRoom = [[XMPPRoom alloc] initWithRoomStorage：xmppRoomCoreDataStorage jid：groupJabId dispatchQueue：dispatch_get_main_queue（）]; [_xmppRoom activate：[[CLXMPPDelegate sharedManager] xmppStream]]; [_xmppRoom addDelegate：self delegateQueue：dispatch_get_main_queue（）]; NSXMLElement * history = [NSXMLElement elementWithName：@「history」]; [history addAttributeWithName：@「maxstanzas」stringValue：@「0」]; [_xmppRoom joinRoomUsingNickname：userMO.closrr_id history：nil]; –

此代碼對我的作品。

XMPPRoomMemoryStorage *roomMemoryStorage = [[XMPPRoomMemoryStorage alloc] init]; 
XMPPRoom *xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:roomMemoryStorage jid:[XMPPJID jidWithString:@"Groupname"] dispatchQueue:dispatch_get_main_queue()]; 
[xmppRoom activate:xmppStream]; 
[xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()]; 
[xmppRoom inviteUser:[XMPPJID jidWithString:@""] withMessage:[NSString stringWithFormat:@"Come Join me"] listusers:@" array with list of users JID "];

來源

2016-02-16 11:57:37

XMPP房間邀請朋友IOS

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