的Django超過PostgreSQL的：使用原始SQL INSERT與返回的不工作

Question

使用PostgreSQL 9.3 + PostGIS的Django的，我想輸入一個記錄，我的表並返回給定id像這樣

def join(request): 
    from django.db import connection, transaction 
    cursor = connection.cursor() 
    id = cursor.execute("insert into table1 values(DEFAULT, 'temp', null,-4, null,null, null, null, DEFAULT, 1,null,DEFAULT,DEFAULT, null) returning id") 
    transaction.set_dirty() 

    return HttpResponse(id) 

這個說法返回None，我如何得到從sql查詢返回的ID

Answer 1

from django.db import connection, transaction 

def join(request): 
    cursor = connection.cursor() 
    id = cursor.execute("insert into table1 values(DEFAULT, 'temp', null,-4, null,null, null, null, DEFAULT, 1,null,DEFAULT,DEFAULT, null)") 
    transaction.set_dirty() 
    last_id = connection.insert_id() 
    return HttpResponse(str(last_id)) 

Answer 2

什麼是您的數據庫後端？如果您使用的sqlite3，

def join(request): 
    from django.db import connection, transaction 
    cursor = connection.cursor() 
    cursor.execute("insert into table1 values(DEFAULT, 'temp', null,-4, null,null, null, null, DEFAULT, 1,null,DEFAULT,DEFAULT, null)") 
    cursor.execute("SELECT last_insert_rowid() FROM table1") 
    id = cursor.fetchone()[0] 
    transaction.set_dirty() 

    return HttpResponse(id)