如何更改shell/bash腳本中的argv [0]值？

Question

set命令可用於更改位置參數的值$ 1 $ 2 ...

但是，有什麼方法可以更改$ 0嗎？

Answer 1

#! /bin/sh 
# try executing this script with several arguments to see the effect 

test ".$INNERCALL" = .YES || { 
    export INNERCALL=YES 
    # this method works both for shell and bash interpreters 
    sh -c ". '$0'" argv0new "$@" 
    exit $? 
} 

printf "argv[0]=$0\n" 
i=1 ; for arg in "$@" ; do printf "argv[$i]=$arg\n" ; i=`expr $i + 1` ; done 

Answer 2

這是另一種方法。它是通過直接執行命令來實現的，這比執行命令（點命令）要好一些。但是，這種方法僅適用於shell解釋，沒有慶典，因爲SH支持-s選項-c一起傳遞：

#! /bin/sh 
# try executing this script with several arguments to see the effect 

test ".$INNERCALL" = .YES || { 
    export INNERCALL=YES 
    cat "$0" | /bin/sh -s -c : argv0new "$@" 
    exit $? 
} 

printf "argv[0]=$0\n" 
i=1 ; for arg in "$@" ; do printf "argv[$i]=$arg\n" ; i=`expr $i + 1` ; done 

的這兩個例子的情況下./the_example.sh 1 2 3預期結果應該是：

argv[0]=argv0new 
argv[1]=1 
argv[2]=2 
argv[3]=3