如何在sql服務器中按星期（7天）分組

Question

希望一切都很好。我有快速的SQL服務器問題：

我想顯示7天增量的星期列。以下是我期望的輸出示例。有沒有辦法在SQL Server中寫入？

Week   Football soccer baseball 
10/01 - 10/07  1  2  3 
10/08 - 10/14  4  5  6 
10/15 - 10/21  5  8  0 

再次感謝！ Joe

這是我的腳本。

CREATE TABLE #TEMP 
(
DT CHAR(10), 
TO_DT CHAR(10), 
BALLs VARCHAR(100), 
PRODUCT INT, 
Week INT 
) 

DECLARE 
@DT DATETIME, 
@TO_DT DATETIME, 
@i INT 

BEGIN 
SET @_DT  = '10/01/2012' 
SET @TO_DT = DATEADD(DAY,7,@_DT) 
set @i=1 


WHILE (@DT <= '12/31/2013') 


BEGIN 
INSERT INTO #TEMP (DT, TO_DT, BALLs, PRODUCT, week) 

SELECT 
CONVERT(CHAR(10),@DT,101)     AS FROM_DT, 
CONVERT(CHAR(10),DATEADD(DAY,-1,@TO_DT),101) AS TO_DT, 
BALLS, 
COUNT(PRODUCT)     AS PRODUCT, 
@I            AS WEEK 
FROM #TABLE 
GROUP BY BALLS 

SET @DT = DATEADD(DAY,7,@DT) 
SET @TO_DT = DATEADD(DAY, 7,@TO_DT) 
set @i = @i + 1 
END 


SELECT * FROM #TEMP 

DROP TABLE #TEMP 

END 

Answer 1

DATEDIFF（WK，0，）應該這樣做。

SELECT 
    DATEDIFF(WK, 0, MyDate) 
    , COUNT(*) 
FROM (VALUES 
('2013-01-01') 
, ('2013-01-02') 
, ('2013-01-03') 
, ('2013-01-04') 
, ('2013-01-05') 
, ('2013-01-06') 
, ('2013-01-07') 
) AS X(MyDate) 
GROUP BY DATEDIFF(WK, 0, MyDate) 

編輯：

隨着日期格式化是這樣的：

SELECT 
    CONVERT(VARCHAR(5), DATEADD(WK, WK, 0), 103) + ' - ' + CONVERT(VARCHAR(5), DATEADD(DD, 6, DATEADD(WK, WK, 0)), 103) 
    , Cnt 
FROM (
    SELECT 
     DATEDIFF(WK, 0, MyDate) AS WK 
     , COUNT(*) AS Cnt 
    FROM (VALUES 
    ('2013-01-01') 
    , ('2013-01-02') 
    , ('2013-01-03') 
    , ('2013-01-04') 
    , ('2013-01-05') 
    , ('2013-01-06') 
    , ('2013-01-07') 
    ) AS X(MyDate) 
    GROUP BY DATEDIFF(WK, 0, MyDate) 
) AS X