好的,SO。經過五個多小時的篩選,找出潛在的重複項,並將可能的解決方案應用到我的項目中,甚至下載一個PHP IDE以確保我的語法對每個人都很好和整潔。我終於到了需要一些建議的地步。當提供正確的登錄憑證時,會話無法啓動
我的兩個問題(這可能與):
當有人登錄,成功地與測試參數我已經存儲在數據庫中,他們是不定向(也許我的if語句是不正確的?)
當頁面加載沒有第一次嘗試時,我的「錯誤密碼 - 用戶名組合」消息正在顯示。我相當肯定爲爲什麼但不是太確定如何解決它。
<?php session_start(); // this line of code has been added by the instruction of a comment.
if(isset($submit)) {
$username = $_POST['username'];
$password = $_POST['password'];
}
$con = mysqli_connect("***","***","***","***");
$S_username = mysqli_real_escape_string($con, $username);
$S_password = mysqli_real_escape_string($con, $password);
if(mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = mysqli_query($con, "SELECT * FROM `users` WHERE `username` = '$S_username' AND `password` = '$S_password'");
if(!$sql) {
die(mysqli_error($con)) ;
}
$check_again = mysqli_num_rows($sql);
if($check_again == 1) {
session_start(); // this line of code has been deleted
$_SESSION['logged in'] = TRUE;
$_SESSION['username'] = $S_username;
header("Location: http://terrythetutor.com/submitvideo.php");
}
else {
echo "Your username and password combination was not recognised. Please try again." ;
}
?>
<html>
<head>
<title>Login Page</title>
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<?php include_once 'googleanalytics.php'; ?>
<body>
<a href="http://terrythetutor.com">
<div class="banner"> </div>
</a>
<?php include 'menu.php'; ?>
<h1 align="center">Please login to access restricted files</h1>
</br>
</br>
</br>
</br>
<div align="center">
<form action = "login.php" method = "post">
Username: <input type = "text" name = "username"></br></br>
Password: <input type = "password" name = "password"></br></br>
<input type = "submit" value = "Login" name="submit">
</form>
</div>
</body>
</html>
任何和所有的反饋是歡迎的。謝謝。
嘗試把'在session_start();'爲您打開'
@ Fred-ii-我加了'session_start();'但不幸的是,它沒有改變任何東西。我應該從if語句中刪除session_start嗎? – user2666324
是的,只有一個,如果你打算把它放在上面。它不能在其他地方(除非你有不同的條件語句)。另外,如果你使用其他文件,他們也需要它。 I.e .:'includes'和'menus'等 –