在單個MySQL語句中計算多個百分比

Question

我是新來的複雜SQL語句，需要幫助。 我已經設法顯示結果集的一半，並與剩餘的掙扎。

需要

結果：

PSU | pregnancy number| pregnancy percentage | % of live birth out of the pregnancy number. 
1 |   2  |   67%   |   40% 
2 |   1  |   33%   |   80% 

下面寫的SQL，我設法拿到第3列。

第二和第三列要求在fieldname = 'Q111'的陳述中。第4列要求與fieldname = 'Q112的聲明的百分比。 如何將不同的where語句組合在一起。

SELECT sms_psu.name1 AS PSU, 
     woman_data.answertext AS NumberOfPreg, 
     Count(woman_data.answertext)/(SELECT Count(woman_data.answertext) 
             FROM woman_data 
               INNER JOIN sms_household 
                 ON woman_data.prim_key = 
                 ms_household.hhid 
               INNER JOIN sms_psu 
                 ON sms_psu.psu = 
                 sms_household.psu 
             WHERE sms_psu.state = 19 
               AND sms_psu.district = 1 
               AND sms_psu.psu = 2 
               AND fieldname = 'Q139') AS 
     totalcpuntpreg 
FROM woman_data 
     INNER JOIN sms_household 
       ON woman_data.prim_key = sms_household.hhid 
     INNER JOIN sms_psu 
       ON sms_psu.psu = sms_household.psu 
WHERE sms_psu.state = 19 
     AND sms_psu.district = 1 
     AND sms_psu.psu = 2 
     AND fieldname = 'Q111' 
GROUP BY woman_data.answertext, 
      sms_household.psu 

---

戈登，你的建議幫了我一個lot.I更新了我的詢問，我有寫，現在是，IAM得到額外一行Q112

PSU accordingly.The問題|懷孕次數|懷孕百分比|懷孕人數中的活產百分比。
1 | 2 | 67％| 40％
2 | 1 | 33％| 80％
2 | 1 | 0％| 20％（第三排是Q112的附加）

但我不需要Q112條目，而我做分組。我可以在case語句和主要where語句中分別使用group嗎？我嘗試用「有」與團體，但力量得到預期的結果。

Answer 1

如上所述，您的查詢是複雜的。不熟悉模式的人很難理解它。因此，我將針對彙總多個項目的查詢提供一般性建議。

使用一個體面的客戶端程序，讓您保存查詢文本。如果它還能打印（格式化）有用的查詢文本。

分別開發和測試每個彙總查詢。確保每個人都獨自一人，從中產生正確的總結結果。

然後，將這些查詢一起加入報告密鑰（我相信您的案例中的PSU），以便生成多個摘要結果。確保它正在工作。

將一個查詢名稱和版本號在評論SELECT語句之後：例如，

SELECT /* pregnancy outcomes 1.1 */ 
     sms_psu.name1 AS PSU, 
     woman_data.answertext AS NumberOfPreg, etc. 

這將讓你使用MySQL SHOW FULL PROCESSLIST找出它的確切查詢正在運行。

最後，如果結果查詢（由大量嵌套子查詢組成）對於您的應用程序需求來說太慢，請對其進行優化。

如果您按照這些步驟操作，那麼您的下一步就是開發您的% live birth彙總查詢，我相信。

Answer 2

您的問題的答案是：CASE聲明。

這個想法是擴展外部的WHERE子句以包含你關心的所有行。然後，在SELECT子句中使用CASE語句來過濾單個變量的行。

我試圖把這個一起：

SELECT sms_psu.name1 AS PSU, 
     woman_data.answertext AS NumberOfPreg, 
     Count(case when sms_psu.state = 19 AND sms_psu.district = 1 AND sms_psu.psu = 2 AND fieldname = 'Q111' 
        then woman_data.answertext 
      end)/
     (SELECT Count(woman_data.answertext) 
     FROM woman_data INNER JOIN 
       sms_household 
       ON woman_data.prim_key = ms_household.hhid INNER JOIN 
       sms_psu 
       ON sms_psu.psu = sms_household.psu 
     WHERE sms_psu.state = 19 AND sms_psu.district = 1 AND sms_psu.psu = 2 AND 
       fieldname = 'Q139' 
     ) AS totalcpuntpreg, 
     Count(case when sms_psu.state = 19 AND sms_psu.district = 1 AND sms_psu.psu = 2 AND fieldname = 'Q112' 
        then woman_data.answertext 
      end)/
     (SELECT Count(woman_data.answertext) 
     FROM woman_data INNER JOIN 
       sms_household 
       ON woman_data.prim_key = ms_household.hhid INNER JOIN 
       sms_psu 
       ON sms_psu.psu = sms_household.psu 
     WHERE sms_psu.state = 19 AND sms_psu.district = 1 AND sms_psu.psu = 2 AND 
       fieldname = 'Q139' 
     ) AS totalcpuntpreg 

FROM woman_data INNER JOIN 
    sms_household 
    ON woman_data.prim_key = sms_household.hhid INNER JOIN 
    sms_psu 
    ON sms_psu.psu = sms_household.psu 
WHERE sms_psu.state = 19 AND sms_psu.district = 1 AND sms_psu.psu = 2 AND 
     fieldname in ('Q111', 'Q112') 
GROUP BY woman_data.answertext 
     sms_household.psu 

不過，我可能會錯過一些細節。

Answer 3

也許是這樣的：

SELECT sms_psu.name1 AS PSU, 
     woman_data.answertext AS NumberOfPreg, 
     SUM(fieldname = 'Q111')/SUM(fieldname = 'Q139') AS pregnancyPercentage, 
     SUM(fieldname = 'Q112')/SUM(fieldname = 'Q139') AS liveBirthPercentage 
FROM woman_data 
     INNER JOIN sms_household 
       ON woman_data.prim_key = sms_household.hhid 
     INNER JOIN sms_psu 
       ON sms_psu.psu = sms_household.psu 
WHERE sms_psu.state = 19 
     AND sms_psu.district = 1 
     AND sms_psu.psu = 2 
GROUP BY woman_data.answertext, 
      sms_household.psu 
HAVING SUM(fieldname = 'Q111') > 0 

查詢第一像以前那樣所有fieldname值，並將它們分組相同的檢索行。計數時，根據需要只計算特定的fieldname條目（使用SUM(condition)技巧）。要確保輸出僅包含具有fieldname = 'Q111'行的組，則添加SUM(fieldname = 'Q111') > 0條件（作爲HAVING子句）。