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我是一種PHP和Codeigniter的新手。我想比較2個不同的數組(一個用字符串和一個用對象(stdClass)),並計算它們的相似值,來計算結果。是否有任何可能解決這個問題,比如轉換對象?爲字符串,反之亦然任何幫助將不勝感激PHP/Codeigniter比較對象(stdClass)和字符串數組array_intersect
這是一些代碼我現在所擁有的:
Result.php
$countcorrectuser = count(array_intersect($_SESSION['correctanswers'], $_SESSION['useranswers']));
$countcorrect = count($_SESSION['correctanswers']);
$totalresult = $countcorrectuser/$countcorrect;
$this->session->set_userdata('totalresult', $totalresult);
Run.php
// $_SESSION['correctanswers']
$correctanswers = $this->Question_model->getAllAnswers();
$this->session->set_userdata('correctanswers', $correctanswers);
// $_SESSION['useranswers'] When the next question submit button is pressed
if(!isset($_SESSION['useranswers'])){
$_SESSION['useranswers'] = array();
}
$_SESSION['useranswers'][] = $this->input->post('useranswer');
Question_model.php的var_dump的
function getAllAnswers(){
$query = $this->db->query('SELECT answer FROM question WHERE exam_id = \'' . $_SESSION['examid'] .'\'');
return $query->result();
}
實施例($ _ SESSION [ 'correctanswers']);
array(4) { [0]=> object(stdClass)#25 (1) { ["answer"]=> string(6) "answer" } etc.
var_dump($ _ SESSION ['usersanswers']);
array(4) { [0]=> string(6) "answer" etc.
感謝您的回覆。對象現在是數組,就像數組中的數組一樣。像這樣:array(4){[0] => array(1){[「answer」] => string(6)「answer」}等。有沒有辦法將數組中的數組轉換爲字符串一個數組?我得到這個錯誤:消息:數組到字符串的轉換 – user1992
簽出我的修訂答案。 – DFriend
非常感謝!現在正在工作。 – user1992