2015-05-20 51 views
-1

我想要做的是將自定義視圖添加到我的活動中,並隨意將其拖放到我想要的任何位置。我創建了一個新的類「Square」。當我構造一個新的Square時,它顯示在顯示屏的左上角。當我設置X和Y座標時,它會消失。如果我將X和Y設置爲30,我會發現Square是單獨顯示的。因此,我的視圖似乎只顯示在顯示屏左上角的一個小框架中。
請幫我移動我的自定義視圖或顯示。謝謝!自定義視圖只顯示在左上角

MainActivity:

private Button btnNewSquare; 
private RelativeLayout relativeLayout; 
private Square[] square = new Square[10]; 
int squareId = 0; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 
    btnNewSquare = (Button)findViewById(R.id.button1); 
    relativeLayout = (RelativeLayout)findViewById(R.id.RelativeLayout); 

    btnNewSquare.setOnClickListener(this); 
} 


@Override 
public void onClick(View v) { 
    // TODO Auto-generated method stub 
    if(v == btnNewSquare) { 
     squareId++; 
     square[squareId] = new Square(this); 
     square[squareId].setX(30); 
        square[squareId].setY(30); 
     square[squareId].setOnTouchListener(square[squareId]); 
     relativeLayout.addView(square[squareId]); 
     relativeLayout.invalidate(); 
     Toast.makeText(getApplication(), "Square" + squareId, Toast.LENGTH_SHORT).show();   
     square[squareId].invalidate();   
    } 
} 

廣場

private int squareWidth = 100; 
private Paint paint; 

public Square(Context context) { 
    super(context); 
    initSquare(); 
    // TODO Auto-generated constructor stub 
} 

public Square(Context context, AttributeSet attrs) { 
    super(context, attrs); 
    initSquare(); 
} 

private final void initSquare() { 
    paint = new Paint(); 
} 

@Override 
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) { 

    setMeasuredDimension(squareWidth, squareWidth); 
} 

@Override 
protected void onDraw(Canvas canvas) {  
    //super.onDraw(canvas); 
    paint.setStyle(Style.FILL); 
    paint.setColor(Color.BLACK); 
    paint.setStrokeWidth(3); 
    canvas.drawRect(getX(), getY(), getX() + squareWidth, getY() + squareWidth, paint); 
} 

@Override 
public boolean onTouch(View v, MotionEvent event) { 
    if (event.getAction() == MotionEvent.ACTION_UP) { 
     v.setVisibility(View.VISIBLE); 
    } 
    return false; 
} 

我的XML

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" 
    xmlns:tools="http://schemas.android.com/tools" 
    android:layout_width="match_parent" 
    android:layout_height="match_parent" 
    android:id="@+id/RelativeLayout" 
    tools:context="${relativePackage}.${activityClass}" > 

    <Button 
     android:id="@+id/button1" 
     android:layout_width="wrap_content" 
     android:layout_height="wrap_content" 
     android:layout_alignParentBottom="true" 
     android:layout_centerHorizontal="true" 
     android:layout_marginBottom="38dp" 
     android:text="New Square" /> 

</RelativeLayout> 
+0

我進一步調查。它與拖放無關。我在創建我的廣場時將X和Y設置爲30,僅繪製了partilly。看起來應用程序左上角有一些面具,方塊只顯示在那裏。 – AlexS

回答

0

答案很簡單。 onDraw()方法中的座標屬於視圖,而不屬於屏幕。所以如果我通過拖放來移動我的視圖(500,500),我必須在onDraw方法中繪製我的矩形仍然在(0,0,100,100)而不是在(500,500,600,600),所以正確的代碼行爲:

canvas.drawRect(0,0,squareWidth,squareWidth,paint);

和不

canvas.drawRect(的getX(),的getY(),的getX()+ squareWidth,的getY()+ squareWidth,油漆);