如何獲取沒有重複記錄的列表？

我需要得到一個沒有重複記錄值的列表。請查看查詢列表以瞭解詳細信息。如何獲取沒有重複記錄的列表？

從原始表中查詢第一個列表，第二個列表是添加兩個函數的中間結果，第三個列表是預期結果。

請幫助獲得第三個列表結果，任何機構可以幫助將非常感激。

順便說一下，困難的部分是需要在最終結果中保留plsh.plsh_id，所以不能在第二個列表中使用不同。 current_smc_value和previous_smc_value需要保持繼續。

的原始數據如下圖所示：

select plsh.plsh_id, 
     plsh.patr_id, 
     plsh.smc   CURRENT_SMC, 
     plsh.create_date CURRENT_SMC_DATE 
    from pat_liver_smc_his plsh 
where plsh.patr_id = 34461 
order by plsh.plsh_id desc;

，其結果是

PLSH_ID PATR_ID CURRENT_SMC CURRENT_SMC_DATE 
1 10020 34461  22  2/19/2013 1:23:58 PM 
2 10019 34461  22  2/19/2013 1:22:57 PM 
3 10018 34461  27  2/19/2013 1:22:42 PM 
4 10017 34461  27  2/19/2013 1:22:42 PM 
5 10016 34461  27  2/19/2013 1:22:32 PM 
6 10015 34461  27  2/19/2013 1:22:32 PM 
7 10014 34461  27  2/19/2013 1:22:20 PM 
8 10013 34461  27  2/19/2013 1:22:20 PM 
9 10012 34461  27  2/19/2013 1:22:09 PM 
10 10011 34461  27  2/19/2013 1:21:50 PM 
11 10010 34461  24  2/19/2013 1:21:36 PM 
12 10009 34461  22  2/19/2013 1:21:06 PM 
13 10008 34461    2/19/2013 1:21:06 PM

要求需要得到previous_smc，previous_smc_date和TRUNC日期，所以我在下面創建查詢語句和兩種功能。

select plsh.plsh_id, 
     plsh.patr_id, 
     tttt_gen_pkg.get_previous_SMC(plsh.patr_id, plsh.plsh_id) PREVIOUS_SMC, 
     trunc(tttt_gen_pkg.get_previous_SMC_Date(plsh.patr_id, plsh.plsh_id)) PREVIOUS_SMC_DATE, 
     plsh.smc CURRENT_SMC, 
     trunc(plsh.create_date) CURRENT_SMC_DATE 
    from pat_liver_smc_his plsh 
where plsh.patr_id = 34461 
order by plsh.plsh_id desc; 

function get_previous_SMC(p_patr_id varchar2, p_plsh_id varchar2) 
    return number is 
    cursor c_smc is 
    select plsh.smc 
     from pat_liver_smc_his plsh 
    where plsh.patr_id = p_patr_id 
     and plsh.plsh_id < p_plsh_id 
    order by plsh.plsh_id desc; 
    v_rst number; 
begin 
    open c_smc; 
    fetch c_smc 
    into v_rst; 
    close c_smc; 
    return v_rst; 
end; 

function get_previous_SMC_Date(p_patr_id varchar2, p_plsh_id varchar2) 
    return date is 
    cursor c_smc is 
    select plsh.create_date 
     from pat_liver_smc_his plsh 
    where plsh.patr_id = p_patr_id 
     and plsh.plsh_id < p_plsh_id 
    order by plsh.plsh_id desc; 
    v_rst date; 
begin 
    open c_smc; 
    fetch c_smc 
    into v_rst; 
    close c_smc; 
    return v_rst; 
end;

，其結果是

PLSH_ID PATR_ID PREVIOUS_SMC PREVIOUS_SMC_DATE CURRENT_SMC  CURRENT_SMC_DATE 
1 10020 34461  22   2/19/2013    22   2/19/2013 
2 10019 34461  27   2/19/2013    22   2/19/2013 
3 10018 34461  27   2/19/2013    27   2/19/2013 
4 10017 34461  27   2/19/2013    27   2/19/2013 
5 10016 34461  27   2/19/2013    27   2/19/2013 
6 10015 34461  27   2/19/2013    27   2/19/2013 
7 10014 34461  27   2/19/2013    27   2/19/2013 
8 10013 34461  27   2/19/2013    27   2/19/2013 
9 10012 34461  27   2/19/2013    27   2/19/2013 
10 10011 34461  24   2/19/2013    27   2/19/2013 
11 10010 34461  22   2/19/2013    24   2/19/2013 
12 10009 34461     2/19/2013    22   2/19/2013 
13 10008 34461              2/19/2013

的期待最終的結果是象下面這樣：如何獲得呢？ PLSH_ID在最終結果中是必需的，因此不同於上面的查詢語句不起作用。

PLSH_ID PATR_ID PREVIOUS_SMC PREVIOUS_SMC_DATE CURRENT_SMC  CURRENT_SMC_DATE 
1 10020 34461  22   2/19/2013    22   2/19/2013 
2 10019 34461  27   2/19/2013    22   2/19/2013 
3 10018 34461  27   2/19/2013    27   2/19/2013 
10 10011 34461  24   2/19/2013    27   2/19/2013 
11 10010 34461  22   2/19/2013    24   2/19/2013 
12 10009 34461     2/19/2013    22   2/19/2013 
13 10008 34461              2/19/2013

Hi Egor, 

Thank you very much for your effort. After a little bit modify your code I got below result, 
it seems current_smc and current_smc_date order is correct but the previous_smc and previous_smc_date still not correct, 
the result is like below: 

    PLSH_ID PATR_ID PREVIOUS_SMC PREVIOUS_SMC_DATE CURRENT_SMC  CURRENT_SMC_DATE 
1 10020 34461          22    2/19/2013 
2 10019 34461 22    2/19/2013   22    2/19/2013 
3 10018 34461 22    2/19/2013   27    2/19/2013 
4 10017 34461 27    2/19/2013   27    2/19/2013 
5 10010 34461 27    2/19/2013   24    2/19/2013 
6 10009 34461 24    2/19/2013   22    2/19/2013 
7 10008 34461 22    2/19/2013       2/19/2013 

A little bit modify of your code is like below: 

select plsh_id, 
     patr_id, 
     PREVIOUS_SMC, 
     PREVIOUS_SMC_DATE, 
     CURRENT_SMC, 
     CURRENT_SMC_DATE 
    from (select plsh_id, 
       patr_id, 
       CURRENT_SMC, 
       CURRENT_SMC_DATE, 
       PREVIOUS_SMC, 
       PREVIOUS_SMC_DATE, 
       case 
       when decode(CURRENT_SMC, 
          lag(CURRENT_SMC) over(partition by t1.patr_id 
            order by t1.plsh_id desc), 
          1) = 1 and decode(CURRENT_SMC_DATE, 
               lag(CURRENT_SMC_DATE) 
               over(partition by t1.patr_id 
                order by t1.plsh_id desc), 
               1) = 1 and 
         decode(PREVIOUS_SMC, 
          lag(PREVIOUS_SMC) 
          over(partition by t1.patr_id order by 
            t1.plsh_id desc), 
          1) = 1 and 
         decode(CURRENT_SMC, 
          lag(CURRENT_SMC) over(partition by t1.patr_id 
            order by t1.plsh_id desc), 
          1) = 1 then 
        1 
       end as the_same 
      from (select plsh.plsh_id, 
         plsh.patr_id, 
         trunc(plsh.smc) CURRENT_SMC, 
         trunc(plsh.create_date) CURRENT_SMC_DATE, 
         lead(trunc(plsh.smc)) over(partition by plsh.patr_id order by plsh.plsh_id) PREVIOUS_SMC, 
         lead(trunc(plsh.create_date)) over(partition by plsh.patr_id order by plsh.plsh_id) PREVIOUS_SMC_DATE 
        from pat_liver_smc_his plsh 
       where plsh.patr_id = 34461) t1) 
where the_same is null 
order by patr_id, plsh_id desc; 

Can you please help me to correct it? Some of you code I don't understand because you are more senior level than me. Thanks again!!!

最終完美的作品版本是從DazzaL。修改後的工作代碼如下：

select plsh_id, 
     patr_id, 
     previous_smc, 
     previous_smc_date, 
     current_smc, 
     current_smc_date 
    from (select plsh_id, 
       patr_id, 
       previous_smc, 
       previous_smc_date, 
       current_smc, 
       current_smc_date, 
       row_number() over(partition by patr_id, current_smc, previous_smc order by plsh_id desc) rn 
      from (select plsh_id, 
         patr_id, 
         plsh.smc current_smc, 
         plsh.create_date current_smc_date, 
         lag(plsh.smc) over(partition by patr_id order by plsh_id) previous_smc, 
         lag(plsh.create_date) over(partition by patr_id order by plsh_id) previous_smc_date 
        from pat_liver_smc_his plsh)) 
where rn = 1 and patr_id = 34461 
order by patr_id, plsh_id desc

來源

2013-03-13 Deep in Development

什麼重複是你想刪除？您的預期結果也有重複。 – 2013-03-13 15:56:28

我對你的示例輸出有點困惑。你試圖刪除的重複行究竟是什麼？你可以在你的例子中標記它們嗎？第二個至第二個輸出似乎沒有重複的行。 – woemler 2013-03-13 15:57:20

行4,5,6,7,8,9具有相同的PREVIOUS_SMC，PREVIOUS_SMC_DATE CURRENT_SMC和CURRENT_SMC_DATE。最終用戶需要獲取列表以查看一天內smc值的變化。 – 2013-03-13 16:01:06

select plsh_id, 
     patr_id, 
     CURRENT_SMC, 
     CURRENT_SMC_DATE, 
     PREVIOUS_SMC, 
     PREVIOUS_SMC_DATE 
from (
    select plsh_id, 
      patr_id, 
      CURRENT_SMC, 
      CURRENT_SMC_DATE, 
      PREVIOUS_SMC, 
      PREVIOUS_SMC_DATE, 
      case when 
      decode(CURRENT_SMC, lag(CURRENT_SMC) over (partition by plsh.patr_id order by plsh.plsh_id desc), 1) = 1 
      and 
      decode(CURRENT_SMC_DATE, lag(CURRENT_SMC_DATE) over (partition by plsh.patr_id order by plsh.plsh_id desc), 1) = 1 
      and 
      decode(PREVIOUS_SMC, lag(PREVIOUS_SMC) over (partition by plsh.patr_id order by plsh.plsh_id desc), 1) = 1 
      and 
      decode(CURRENT_SMC, lag(CURRENT_SMC) over (partition by plsh.patr_id order by plsh.plsh_id desc), 1) = 1 
      then 1 
      end as the_same 
    from (
     select 
      plsh.plsh_id, 
      plsh.patr_id, 
      trunc(plsh.smc)   CURRENT_SMC, 
      trunc(plsh.create_date) CURRENT_SMC_DATE, 
      lead(trunc(plsh.smc)) over (partition by plsh.patr_id order by plsh.plsh_id) PREVIOUS_SMC, 
      lead(trunc(plsh.create_date)) over (partition by plsh.patr_id order by plsh.plsh_id) PREVIOUS_SMC_DATE 
     from pat_liver_smc_his plsh 
     where plsh.patr_id = 34461 
    ) 
) 
where the_same is null 
order by plsh.patr_id, plsh.plsh_id desc;

來源

2013-03-13 16:26:23

嗨葉戈爾，請看看我上面發佈的問題的修改版本，其中有你的答案的結果，它仍然需要花費更多的努力才能達到最終結果。謝謝！！！！！！ – 2013-03-13 17:46:21

@Matthew - 對不起，這是我的錯。請將'lead'替換爲'lag'。 – 2013-03-13 18:23:31

謝謝Egor !!!!!!!!!!!!!!! – 2013-03-13 18:39:35

類似;

select plsh_id, patr_id, previous_smc, previous_smc_date, 
     current_smc, current_smc_date 
    from (select plsh_id, patr_id, previous_smc, 
       previous_smc_date, current_smc, 
       current_smc_date, 
       row_number() over(partition by patr_id, current_smc, 
           current_smc_date, previous_smc, 
           previous_smc_date 
           order by plsh_id desc) rn   
      from (select plsh_id, patr_id, current_smc, 
         trunc(current_smc_date) current_smc_date, 
         lag(current_smc) over(partition by patr_id 
              order by plsh_id) previous_smc, 
         trunc(lag(current_smc_date) 
           over(partition by patr_id 
            order by plsh_id)) previous_smc_date 
        from pat_liver_smc_his)) 
where rn = 1 
order by patr_id, plsh_id desc

來源

2013-03-13 17:46:47 DazzaL

感謝DazzaL !!!!!!!!!!!!!!它工作完美!!!!!!!!!!! – 2013-03-13 18:38:57

如何獲取沒有重複記錄的列表？

回答

相關問題