SQL查詢：具有最高工資從每家公司選擇員工，

嗨，我已經寫了Derby數據庫的SQL查詢，其獲取具有最高工資SQL查詢：具有最高工資從每家公司選擇員工，

這些都是表結構

create table Company_Tbl_One(
    company_Id int primary key, 
    company_name varchar(100) 
) 

create table Employee_Tbl_One(
    employee_Id int primary key, 
    employee_name varchar(100), 
    company int references Company_Tbl_One 
) 

alter table Employee_Tbl_One add salary int 

insert into Company_Tbl_One values(12,'Facebook Inc'); 
insert into Company_Tbl_One values(11,'Google Inc'); 
insert into Company_Tbl_One values(10,'Yahoo Inc'); 
insert into Company_Tbl_One values(14,'AOL Inc'); 

insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(1, 'Tom Jackson',12,1000); 
insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(2, 'Jimmy John',12,200); 
insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(3, 'Samual Jackson',11,2000); 
insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(4, 'Sam Raime',10,3000); 
insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(5, 'Tidy Mann',14,5000); 
insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(6, 'Oliver Stone',14,5300); 
insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(7, 'Falcon Gonzalies',10,3300); 
insert into EMPLOYEE_TBL_ONE(employee_Id,employee_name,company,salary) values(8, 'Ister Jack',11,2300);

從每家公司的員工

的SQL查詢如下

select e.employee_name, c.company_name 
from EMPLOYEE_TBL_ONE e, 
    COMPANY_TBL_ONE c, 
    (select max(salary) as SALARY, 
      company as COMPANY_ID 
      from EMPLOYEE_TBL_ONE group by COMPANY) x 
where c.company_Id = x.COMPANY_ID 
and  e.salary = x.SALARY 
and  e.company = c.company_Id

現在上面的SQL查詢工作正常，並獲取我的結果，

但是，有沒有其他方式來編寫SQL查詢相同的問題陳述？

來源

2014-09-22 Rahul Shivsharan

不相關但是：你應該開始在FROM子句中使用顯式的'JOIN'而不是在where子句中的隱式連接。關於你的問題：由於德比缺乏窗口功能，我沒有看到另一種方法來實現你想要的。 – 2014-09-22 12:39:34

爲什麼你需要多種方式來編寫你的查詢？是由於某種原因你認定的不合適嗎？ – 2014-09-22 14:14:04

使用not exists即選擇其中具有更高的薪水其他員工不存在

select e.employee_name, c.company_name, e.salary 
from EMPLOYEE_TBL_ONE e 
join COMPANY_TBL_ONE c on e.company = c.company_Id  
where not exists (
    select 1 from EMPLOYEE_TBL_ONE e2 
    where e2.company = e.company 
    and e2.salary > e.salary 
)

來源

2014-09-22 12:46:56 FuzzyTree

您可以使用SQL

的功能RANK

SELECT * 
FROM Company_Tbl_One C 
INNER JOIN 
(
    SELECT *, RANK() OVER(PARTITION BY Company ORDER BY Salary DESC) AS rank 
    FROM Employee_Tbl_One 
) E 
ON C.company_Id = E.company 
AND E.rank = 1

編輯所有員工的另一種方式：對不起，認爲這是MSSQL

來源

2014-09-22 13:15:28 GercoOnline

SQL查詢：具有最高工資從每家公司選擇員工，

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