我有兩個表，我用UNION ALL查詢 - 一個用於Android，一個用於iPhone。每個表都有自己的設備字段（「android」或「iphone」）。MySQL中的GROUP_CONCAT - 如何包含不同的值？
我使用GROUP_CONCAT(DISTINCT `device` ORDER BY `device` SEPARATOR ', ') AS `device`幾次，每次當我被另一個列組（如日期，USER_ID等）。我也使用相同的GROUP_CONCAT來計算總數。
的問題是，當I組由日期，我選擇設備（未直接在設備）的GROUP_CONCAT因爲有一些日期那裏有Android和iPhone購買。選擇還包括WHERE或HAVING讓用戶按特定日期過濾，加入日期等的用戶數。當我計算總計時，我在設備上有GROUP_CONCAT，它本身是一個GROUP_CONCAT函數。結果可能類似於「android，android，iphone，iphone」，因爲只有Android的日期，僅有iPhone的日期和兩者的日期（其他查詢只能有一個或一些這些選項）。我正在尋找一種方法將此結果轉換爲「android，iphone」。
目前我使用PHP函數：
private function get_device_human_string($fp_device_computer_string)
{
$devices= array(
'android' => 'Android',
'iphone' => 'iPhone'
);
$device_computer_string= strtolower($fp_device_computer_string);
$ret= array();
foreach ($devices as $device_key => $device_human_string)
{
if (strpos($device_computer_string, $device_key) !== false)
{
$ret[]= $device_human_string;
}
}
return implode(', ', $ret);
}
但是我正在尋找一種方式來做到這一點在MySQL（返回的結果也應該有一個大寫的A中的「Android」和資本P在「iPhone」中，但我不介意使用PHP函數）。
順便說一下，總的SELECT查詢是SELECT .... FROM（SELECT .... FROM（.... UNION ALL ....）GROUP BY ....）和GROUP BY在裏面。如果我沒有在內部查詢中包含設備，那麼在外部查詢中將不會有設備到GROUP_CONCAT。所以我不能直接在設備上進行GROUP_CONCAT。
編輯：這是我使用（在WHERE和HAVING可根據用戶的過濾器改變）查詢的例子：
SELECT
COUNT(1) AS `count`,
SUM(`joined`) AS `joined`,
SUM(`users`) AS `users`,
SUM(`purchases`) AS `purchases`,
SUM(`credits_purchased`) AS `credits_purchased`,
GROUP_CONCAT(DISTINCT `device` ORDER BY `device` SEPARATOR ', ') AS `device`,
GROUP_CONCAT(DISTINCT `application` ORDER BY `application` SEPARATOR ', ') AS `application`
FROM (
SELECT
`all_purchases`.*,
IF(`users_joined`.`joined` IS NOT NULL, `users_joined`.`joined`, 0) AS `joined`,
'esalne' AS `application`
FROM (
SELECT
DATE(`date`) AS `date`,
COUNT(DISTINCT `user_id`) AS `users`,
COUNT(1) AS `purchases`,
SUM(
IF(
STRCMP(SUBSTRING(`item`, 1, CHAR_LENGTH('esalne.sip.')), 'esalne.sip.')=0,
CAST(SUBSTRING(`item`, CHAR_LENGTH('esalne.sip.')+1) AS UNSIGNED INTEGER),
0
)
) AS `credits_purchased`,
GROUP_CONCAT(DISTINCT `device` ORDER BY `device` SEPARATOR ', ') AS `device`
FROM (
(
SELECT
`id`,
`item`,
`date`,
`status`,
`user` AS `user_id`,
NULL AS `transaction_id`,
'android' AS `device`
FROM `enswitch_android_purchases`
WHERE (`status`=1)
AND (`user` IS NOT NULL)
)
UNION ALL
(
SELECT
`id`,
`item`,
`date`,
`status`,
`user` AS `user_id`,
`transaction_id`,
'iphone' AS `device`
FROM `enswitch_iphone_purchases`
WHERE (`status`=1)
AND (`user` IS NOT NULL)
)
) AS `all_purchases`
GROUP BY DATE(`date`)
) AS `all_purchases`
LEFT JOIN (
SELECT
`join_date` AS `date`,
COUNT(1) AS `joined`
FROM (
SELECT
`user_id`,
MIN(DATE(`date`)) AS `join_date`
FROM (
(
SELECT
`id`,
`item`,
`date`,
`status`,
`user` AS `user_id`,
NULL AS `transaction_id`,
'android' AS `device`
FROM `enswitch_android_purchases`
WHERE (`status`=1)
AND (`user` IS NOT NULL)
)
UNION ALL
(
SELECT
`id`,
`item`,
`date`,
`status`,
`user` AS `user_id`,
`transaction_id`,
'iphone' AS `device`
FROM `enswitch_iphone_purchases`
WHERE (`status`=1)
AND (`user` IS NOT NULL)
)
) AS `all_purchases`
GROUP BY `user_id`
) AS `users`
GROUP BY `date`
) AS `users_joined` ON (`all_purchases`.`date`=`users_joined`.`date`)
HAVING (`date` >= DATE_ADD('2012-11-01', INTERVAL 0 DAY))
AND (`date` < DATE_ADD('2012-11-30', INTERVAL 1 DAY))
AND (`joined` >= 2)
AND (`purchases` <= 30)
AND (`credits_purchased` <= 3000)
) AS `all_purchases_by_dates`
感謝， URI。
沒有人可以幫助你，如果你不發佈實際查詢。 –