用PHP echo語句生成JSON

Question

我試圖建立從一個PHP數組 JSON數組這是我在我的控制器功能

function latest_pheeds() { 
      if($this->isLogged() == true) { 
      $this->load->model('pheed_model'); 
      $data = $this->pheed_model->get_latest_pheeds(); 
      $last = end($data); 
      echo "["; 
       for($i = 0; $i < count($data); $i++) { 
        echo '{"user_id":"'.$data[$i][0]['user_id'].'",'; 
        echo '"pheed_id":"'.$data[$i][0]['pheed_id'].'",'; 
        echo '"pheed":"'.$data[$i][0]['pheed'].'",'; 
        echo '"datetime":"'.$data[$i][0]['datetime'].'",'; 
         if($i == count($data)) { 
         echo '"comments":"'.$data[$i][0]['comments'].'"}'; 
         }else { 
          echo '"comments":"'.$data[$i][0]['comments'].'"},'; 
         } 
        } 

       echo "]"; 
      } 
      return false; 
    } 

它返回一個JSON數組這樣

[{"user_id":"9","pheed_id":"2","pheed":"This is my first real pheed, its got potential ","datetime":"1313188898","comments":"0"},{"user_id":"9","pheed_id":"11","pheed":"My stomach being hurting all day","datetime":"1313422390","comments":"0"},{"user_id":"9","pheed_id":"11","pheed":"My stomach being hurting all day","datetime":"1313422390","comments":"0"},{"user_id":"9","pheed_id":"10","pheed":"Thank God for stackoverflow.com ","datetime":"1313358605","comments":"0"},] 

但我似乎無法訪問它與jquery

Answer 1

已經投了@derekerdmann，但想到我要補充...

你的代碼將工作，如果你改變：

if($i == count($data)) { 

到

if($i == count($data) - 1) { 

但是，不要't這樣做。如果您只是將$data陣列的每個成員的所有內容都放入json中，那麼您應該只能使用json_encode($data)。如果您只抽取某些部分，則建立一個已過濾數據的輔助數組，然後json_encode。

function latest_pheeds() { 
    if($this->isLogged() == true) { 
     $this->load->model('pheed_model'); 
     $data = $this->pheed_model->get_latest_pheeds(); 
     $filtered_items = array(); 
     foreach ($data as $member) { 
      $filtered_item = array(); 
      $filtered_item['user_id'] = $member['user_id']; 
      $filtered_item['pheed_id'] = $member['pheed_id']; 
      ... 
      ... 
      $filtered_items[] = $filtered_item; 
     } 
     echo json_encode($filtered_items); 
    } 
    return false; 
} 

Answer 2

我相信問題在於數組結尾的尾隨逗號。

而不是嘗試自己編碼，請使用PHP的json_encode函數。它經過多次測試和驗證，因此您不必重新發明輪子。