錯誤處理python

-1

試圖做一個簡單的錯誤處理，看看主機是否無法訪問，我一直得到一個無效的語法except。錯誤處理python

import socket    

s = socket.socket()   
host = "" 
port = 1337    

print(""" 
============================================ 
Welcome to Coder77's local internet messager 
============================================ 
The current soon to be encrypted server is {0} 
""".format(host)) 

host = input("Please select the IP you would like to communicate to: ") 
print("Now connecting to {0}....".format(host)) 

try: 
     s.connect((host, port) 
except socket.error as s: 
     print ("Host is unreachable") 


print (s.recv(2048)) 
input("Close") 
s.close()

來源

2014-02-13 Coder77

規則：每當你得到一個奇怪的語法錯誤，看看在*之前*網上看到如果括號，括號和括號是平衡的。 –

s.connect((host, port)

應該是拇指

s.connect((host, port))

來源

2014-02-13 12:23:28 jonjohnson

變化s.connect((host, port)到s.connect(host, port)

來源

2014-02-13 12:21:15 gariel

不，它應該是's.connect（（主機，端口））'。 ['socket.connect（）']（http://docs.python.org/2/library/socket.html#socket.socket.connect）只需*一個*參數。 –

錯誤處理python

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