升壓池替代釋放calloc

Question

所有，

如果使用升壓池庫，你會如何替換以下語句：

MyStruct *someStruct = (MyStruct *) calloc(numOfElements, sizeof(MyStruct)); 

如果它是一個元素，我會做：

boost::object_pool<MyStruct> myPool; 
MyStruct *someStruct = myPool.malloc(); 

但由於「numOfElements」是一個變量，我有感覺執行一個malloc（）循環不是一個好主意嗎？

Answer 1

我說你需要使用pool_alloc接口：

static pointer allocate(size_type n); 
static pointer allocate(size_type n, pointer); 
static void deallocate(pointer ptr, size_type n); 

樣品從http://www.boost.org/doc/libs/1_47_0/libs/pool/doc/interfaces.html

void func() 
{ 
    std::vector<int, boost::pool_allocator<int> > v; 
    for (int i = 0; i < 10000; ++i) 
     v.push_back(13); 
} // Exiting the function does NOT free the system memory allocated by the pool allocator 
    // You must call 
    // boost::singleton_pool<boost::pool_allocator_tag, sizeof(int)>::release_memory() 
    // in order to force that