爲什麼calculator.getValue（）總是0？

Question

我是一名java學生，我正致力於讓我的代碼更加面向對象。我可以很容易地在主代碼計算器，但我真的很努力用方法來實現它。以下代碼將始終返回0 ...但目標是創建一個允許用戶在一行中輸入運算符和數字的程序（示例+5），代碼應該輸出前一個值，新值以及允許重置。我相信，我真的很接近解決這一併且只需要一個點在正確的方向..

輸出

Enter an operator and a number: 
+5 
0.0 

計算器類

import java.util.Scanner; 
public class Calculator { 
    private final int RESET = 0; 
    private double number = 0; 
    private double result = 0; // I believe this is the issue but how can I resolve it? 
    private char operator; 
    private static Scanner keyboard = new Scanner(System.in); 
    public Calculator(double number) 
    { 
     this.number = number; 

    } 
    // this method invokes the whatOperator() to create a new result 
    // the edited method still returns 0 
    public double aResult(Calculator other) 
{ 

    other.whatOperator(); 
    this.result = other.result; 
    return result; 

} 
    // I created this method in hopes that it would do most of the work..when I invoke it and enter my operator and number it does not seem to function correctly 
    public void whatOperator() 
    { 

     String operator = null; 
     operator = enterNumber(); 
     double theNumber = Double.parseDouble(operator); 
     char theOperator =operator.charAt(0); 
     operator = null; 
     operator += theOperator; 

     // switch method to find the operator 
     switch(operator){ 
     case "*": 
     result = getNumber() * theNumber; 
     break; 
     case "/": 
     result = getNumber()/theNumber; 
     break; 
     case "+": 
     result = getNumber() + theNumber; 
     break; 
     case "-": 
     result = getNumber() - theNumber; 
     break; 
     case "R": 
     result = RESET; 
     break; 
    } 


} 
// methods for operation...I was hoping to not use these 
public double add(double secondNumber) 
{ 
    result = number + secondNumber; 
    return result; 

} 
public double divide(double secondNumber) 
{ 
    result = number/secondNumber; 
    return result; 
} 
public double multiply(double secondNumber) 
{ 
    result = number * secondNumber; 
    return result; 
} 
public void subtract(double secondNumber) 
{ 
    result = number - secondNumber; 
} 
public double getNumber() 
{ 
    return number; 
} 
    // method for getting input 
public static String enterNumber() 
    { 

     System.out.println("Enter an operator and a number:"); 
     String toString = keyboard.nextLine(); 
     return toString; 
    } 

    public static void main (String[] args) { 
     // the calculator is initialized at 0 
     Calculator a = new Calculator(0); 
     // now I create a second calculator with the result from the aResult() 
     Calculator b = new Calculator(a.aResult(a)); 
     // why is b.getNumber() = 0 at this point? 
     String theString = String.valueOf(b.getNumber()); 
     // prints 0 every time 
     System.out.println(theString); 




     } 

    } 

Answer 1

有在你的代碼的一些錯誤。

public double aResult(Calculator other) 
{ 
    other = new Calculator(getNumber()); 
    other.whatOperator(); 
    this.result = result; 
    return result; 

} 

該行this.result =結果沒有任何意義。我想你想用whatOperator（）來返回結果的方法，例如

this.result = other.whatOperator(); 

我也認爲你不想重寫「其他」計算器。你從不使用新的計算器。但是你想在主要方法中打印新計算器的輸出。因爲你從來沒有使用過的新的計算器，輸出爲0

Answer 2

在你aResult方法，則需要啓動計算器

public double aResult(Calculator other) { 
    //other = new Calculator(getNumber()); // this should not be here 
    other.whatOperator(); 
    this.result = result; 
    return result; 

} 

Answer 3

解決問題的另一個新的實例：

//change 
this.result = result; //this does nothing 
//to 
this.result = other.result; //this changes the result to the new value 
//erase this line 
other = new Calculator(getNumber()); // do not need to create a new calculator 

變化whatOperator爲double並返回一個double的方法