例如,我有3個表格; 表1:如何計算3個不同表格中兩列的總值?
+-------+
| count |
+-------+
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
+-------+
表2:
+-------+
| count |
+-------+
| 3 |
| 0 |
| 0 |
| 0 |
| 0 |
+-------+
表3:
+-------+
| count |
+-------+
| 1 |
| 1 |
| 0 |
| 0 |
| 1 |
+-------+
我想計算table1.count + table2.count + table3.count,得到的結果,table_right :
+-------+
| count |
+-------+
| 5 | (1+3+1=5)
| 1 | (0+0+1=1)
| 0 | (0+0+0=0)
| 0 | (0+0+0=0)
| 4 | (3+0+1=4)
+-------+
但是,如果我用命令:
select table1.count+table2.count+table3.count as total
from table1,table2,table3;
結果將成爲:
+-------+
| total |
+-------+
| 5 |
| 4 |
| 4 |
| 4 |
| 7 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 5 |
| 4 |
| 4 |
| 4 |
| 7 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 4 |
| 3 |
| 3 |
| 3 |
| 6 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 4 |
| 3 |
| 3 |
| 3 |
| 6 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 1 |
| 0 |
| 0 |
| 0 |
| 3 |
| 5 |
| 4 |
| 4 |
| 4 |
| 7 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
| 2 |
| 1 |
| 1 |
| 1 |
| 4 |
+-------+
這不是我想要的結果,如果我嘗試
select distinct table1.count+table2.count+table3.count as total
from table1,table2,table3;
我會得到:
+-------+
| total |
+-------+
| 5 |
| 4 |
| 7 |
| 2 |
| 1 |
| 3 |
| 6 |
| 0 |
+-------+
還是不是我想要的結果。我怎麼能得到table_right?
做此列共用一個ID或東西,你可以通過...分組? – josegomezr 2015-02-23 23:13:05
表格代表*無序*集合。行之間沒有對應關係,除非您有列來表達這種關係。 – 2015-02-23 23:16:59
你是否想爲每個表添加一些rowID?如何爲每個表添加自動增加num的rowID? – beasone 2015-02-23 23:23:27