Im做一個計算器c和錯誤彈出，當我嘗試運行它

Question

繼承人的代碼：

#include <stdio.h> 
#include <stdlib.h> 

void main() { 
    int op,a,b; 

    printf("***Welcome to the calculatron***\n\n"); 

    do{ 
     printf("choose an operation\n\n"); 
     print(" 1 : Addition\n 2: Substraction\n 3: Multiplication\n 4: Division"); 
     scanf("%d",&op) 
    }while((op != 1 && (op != 2) && (op != 3) && (op != 4)); 

    printf("Type the first number"); 
    scanf("%d",&op) 
    printf("Type the second number"); 
    scanf("%d",&op); 


    switch(op) 
    case 1: 
     printf("You have chosen the Addition\n"); 
     printf("%d + %d = %d",a,b,a+b); 
     break; 

    case 2: 
     printf("You have chosen the Substraction\n"); 
     printf("%d + %d = %d",a,b,a-b); 
     break; 

    case 3: 
     printf("You have chosen the Multiplication\n"); 
     printf("%d + %d = %d",a,b,a*b); 
     break; 

    case 4: 
     printf("You have chosen the Division\n"); 
     printf("%d + %d = %d",a,b,a/b); 
     break; 
    } 

的錯誤

expected " ; " before " } " token and expected ") " before " ; " token are in lines 13 and 41

我不知道該怎麼辦，請幫忙。

Answer 1

應該有scanf函數後一個分號：

printf("Type the first number"); 
    scanf("%d",&op); 

而且你缺少開關箱的開括號：

switch(op) 
{ 
} 

Answer 2

你也錯過switch後{？仔細檢查編譯器錯誤。並看看你是否錯過了任何的語法。

Answer 3

你缺少後開關（OP）的花手鐲{開放

switch(expression) { 
    case constant-expression : 
     statement(s); 
     break; /* optional */ 

    case constant-expression : 
     statement(s); 
     break; /* optional */ 

    default : /* Optional */ 
    statement(s); 
} 

Answer 4

有你的程序中的幾個誤區。

對於初學者main函數不帶參數應該用C像

int main(void) 
{ 
    //... 
} 

聲明你忘了把分號語句與scanf例如在這個編碼塊

do{ 
    printf("choose an operation\n\n"); 
    print(" 1 : Addition\n 2: Substraction\n 3: Multiplication\n 4: Division"); 
    scanf("%d",&op) 
    // must be scanf("%d, &op); 
}while((op != 1 && (op != 2) && (op != 3) && (op != 4)); 

的條件同時可以寫得更簡單，就像

}while (op < 1 || op > 4); 

如果假定它不應接受負值，則最好聲明變量op的類型爲unsigned int。

在這些語句

printf("Type the first number"); 
scanf("%d",&op) 
printf("Type the second number"); 
scanf("%d",&op); 

你必須爲變量a和b而不是變量op輸入值。

printf("Type the first number"); 
scanf("%d",&a) 
printf("Type the second number"); 
scanf("%d",&b); 

switch語句應該有一個複合語句是你必須在其交換機的聲明中括號

switch(op) 
{ 
    //... 
} 

而且它會很好，包括標籤default的情況下，當用戶將進入無效的操作。

在交換機還printf語句無效文字和運營

case 2: 
    printf("You have chosen the Substraction\n"); 
    printf("%d + %d = %d",a,b,a-b); 
    // should be printf("%d - %d = %d",a,b,a-b); 
    break; 

case 3: 
    printf("You have chosen the Multiplication\n"); 
    printf("%d + %d = %d",a,b,a*b); 
    // should be printf("%d * %d = %d",a,b,a * b); 
    break; 

case 4: 
    printf("You have chosen the Division\n"); 
    printf("%d + %d = %d",a,b,a/b); 
    // should be printf("%d/%d = %d",a,b,a/b); 
    break; 

而且最好是操作的輸出結果有型long long int

例如

printf("You have chosen the Multiplication\n"); 
    printf("%d * %d = %lld", a, b, (long long int)a * b); 
    break; 

Answer 5

你在發佈之前應該檢查你的代碼。此外，您還需要更認真的編碼時，有許多錯誤在你的榜樣（我只說說這裏的do... while，很多人都已經談到了這些錯誤：

• 第二printf()
缺少 f
• 缺少;後scanf()
• 丟失的圓括號您while條件

結果爲：

do { 
    printf("choose an operation\n\n"); 
    printf("1 : Addition\n 2: Substraction\n 3: Multiplication\n 4: Division"); 
    scanf("%d",&op); 
} while ((op != 1) && (op != 2) && (op != 3) && (op != 4)); 

您必須更加嚴謹與您的代碼，學習尤其是當你要小心不要拿壞習慣。