1
座標對如何可以重新排列[(0, 4), (1, 3)]
到(0, 1), (4, 3)
,換句話說組第一座標一起和第二座標一起(爲了維持左到右)。我需要爲大名單做到這一點,下面所示例重新組2D在Python
c = [[(0, 4), (1, 3)],
[(0, 4), (1, 5)],
[(1, 3), (2, 2)],
[(1, 3), (2, 4)],
[(1, 5), (2, 2)],
[(1, 5), (2, 6)],
...]
所以最終結果是
[[(0, 1), (4, 3)],
[(0, 1), (4, 5)],
[(1, 2), (3, 2)],
[(1, 2), (3, 4)],
[(1, 2), (5, 2)],
[(1, 2), (5, 6)],
...
]
太棒了!我tourchured'拉鍊()'太多而忽略了基礎知識。 –