左加入正確的總數，經過計數和總和挑戰

Question

我有一個查詢，我似乎被卡住，我不知道如何解決這個問題。它只是在查詢的中間部分將我拋棄。我只是想用一個左連接來計算和總結一個字段的總成本，並且總和是正確的。我相信問題是如果在同一張桌子上有超過1個與該賬戶相關的項目，它將總結多次，總額將不正確。這裏是我與....

left join 
(select distinct (soid), count(*) as oaccount, sum(amount) as c3 from 
soorderdetails where soorderdetails.description like 'Installation%' or 
soorderdetails.description like 'Training%' or soorderdetails.description 
like 'Fusion Report%' group by soid) as o on o.soid=s.soid 


The result I would like to obtain is: 
    Job# | (c3) | Soid 
    ----- | -----|----- 
    223 | 2000 | 212 (1 record - c3 amount - 1=2000) 
    224 | 300 | 213 (2 record - c3 amount - 1=100 + 2=200) 
    225 | 4333 | 214 (1 record - c3 amount - 1=4333) 
    226 | 1000 | 215 (3 record - c3 amount - 1=200 + 2=300 + 3=500) 

    But I am getting this.... 

    Job# | (c3) | Soid 
    -----| -----|----- 
    223 | 2000 | 212 (1 record...sum is correct here) 
    224 | 600 | 213 (2 record - 1=100x2 + 2=200x2)=WRONG 
    225 | 4333 | 214 (1 record...sum is correct here) 
    226 | 2500 | 215 (3 record - 1=200x3 + 2=300x3 + 3=500x3)=WRONG 

我正在尋找的是與（C3）場的每個不同的總和一起顯示所有不同（soid）記錄奮力一節（ soid）記錄。

所以用上面的查詢，我可以看到C3的總和顯示。如果只有1條記錄，那麼總和顯示正確，如果有超過1條記錄，則記錄數將乘以找到的soid匹配的數量，然後一起加上總和值。我試圖採用一些在這裏找到的解決方案，但仍然無法正確顯示它。任何人都可以提供幫助嗎？先進的謝謝！

• 表1具有匹配soid id字段（s.soid）

• 表2具有soid，描述和量字段（o.soid）

• 我試圖左連接表2到表1通過使用soid字段。

• 我想正確地總結金額領域。現在看來，每個'金額'總和乘以該記錄的計數值。謝謝！

下面是完整的查詢......

SELECT DISTINCT (jobnumber) as l1, 
       c2 as l2, 
       sum(isnull(c3,0)) as l3, 
       sum((isnull(c3,0)/150)*50) as l4, 
       sum(c5) as l5, sum(c6) as l6,sum(c5+c6) as l7, 
       sum(c5*25.27) as l8, 
       isnull(c9,0) as l9, 
       (sum(c5*25.27)+(isnull(c9,0))) as l10, 
       sum((isnull(c3,0)/150)*50)-(sum(c5*25.27) 
             +(isnull(c9,0))) as l11 , 
       sum(isnull(c3,0))-(sum(c5*25.27)+(isnull(c9,0))) as l12 
FROM (
     SELECT DISTINCT (j.jobnumber), 
         customername as c2, 
         c3, 
         c5, 
         c6, 
         c9 
     FROM dbo.SOOrders as s 
     LEFT JOIN (
       SELECT DISTINCT (jobid), 
            COUNT(*) as s9, 
            sum(total) as c9 
       FROM apvouchers 
       GROUP BY jobid 
       ) as v ON v.jobid = s.jobid 
     LEFT JOIN (
       SELECT DISTINCT (soid), 
            COUNT(*) as oaccount, 
            SUM(amount) as c3 
       FROM soorderdetails 
       WHERE description LIKE 'Installation%' 
        OR description LIKE 'Training%' 
        OR description LIKE 'Fusion Report%' 
       GROUP BY soid 
       ) as o ON o.soid = s.soid 
     INNER JOIN sccalls as t ON t.jobid = s.jobid 
     INNER JOIN (
        SELECT DISTINCT(callid), 
            COUNT(*) as myaccount, 
            SUM(actualhours) as c5, 
            SUM(overtimehours) as c6 
        FROM scqreportlabors 
        WHERE actualhours > 0 
        GROUP BY callid 
       ) as r ON r.callid = t.callid 
     LEFT JOIN ShAgents ON AgentID = TechnicianID 
     LEFT JOIN arcustomers as c ON c.customerid = s.customerid 
     INNER JOIN icjobs as j ON j.jobid = s.jobid 
     WHERE j.active = 1 
    ) as x 
GROUP BY jobnumber, c2, c9 
ORDER BY jobnumber DESC 

Answer 1

有兩件事情會在這裏......

你不需要DISTINCT（在你的主選擇）和GROUP BY，這是多餘的。分組就已經做出記錄不同：

LEFT JOIN 
(SELECT soid, COUNT(*) as oaccount, SUM(amount) as c3 
    FROM soorderdetails 
    WHERE soorderdetails.description like 'Installation%' 
    OR soorderdetails.description like 'Training%' 
    OR soorderdetails.description like 'Fusion Report%' 
    GROUP BY soid 
) AS o ON o.soid = s.soid 

我想你所追求的，是添加DISTINCT修改您SUM(amount)只總和唯一值SUM(DISTINCT amount)相當於：

LEFT JOIN 
(SELECT soid, COUNT(*) as oaccount, SUM(DISTINCT amount) as c3 
    FROM soorderdetails 
    WHERE soorderdetails.description like 'Installation%' 
    OR soorderdetails.description like 'Training%' 
    OR soorderdetails.description like 'Fusion Report%' 
    GROUP BY soid 
) AS o ON o.soid = s.soid 

那所有說...基於此：

但是，如果有多個記錄，'金額'得到 乘以記錄

我猜你不想總和在所有號碼：

LEFT JOIN 
(SELECT soid, COUNT(*) as oaccount, amount as c3 
    FROM soorderdetails 
    WHERE soorderdetails.description like 'Installation%' 
    OR soorderdetails.description like 'Training%' 
    OR soorderdetails.description like 'Fusion Report%' 
    GROUP BY soid, amount 
) AS o ON o.soid = s.soid 

這將是巨大的，因爲SUM(DISTINCT..）操作真的破壞性能。