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在python中運行以下代碼時,出現錯誤:提供的綁定數量不正確。當前語句使用0,並提供1。對於查詢語句。在Python中提供的綁定數量不正確Sqlite查詢
conn = sqlite3.connect('viber_messages2')
cur = conn.cursor()
cur = cur.execute("""SELECT DISTINCT messages.conversation_id
FROM messages
INNER JOIN participants ON messages.participant_id = participants._id
WHERE messages.conversation_id IS NOT NULL;""")
query = ("""SELECT messages._id, messages.body, messages.conversation_id, messages.participant_id, participants_info.number, participants_info.contact_name
FROM messages
INNER JOIN
participants ON messages.participant_id = participants._id
INNER JOIN
participants_info ON participants.participant_info_id = participants_info._id;""")
with open('messages.html', 'w') as h, open('test.txt', 'w') as t:
for convo in cur.fetchall():
df = pd.read_sql_query(query, conn, params=convo)
# HTML WRITE
h.write(df.to_html())
h.write('<br/>')
# TXT WRITE
t.write(df.to_string())
t.write('\n\n')
cur.close()
conn.close()
啊,是我的錯!它修復了錯誤,但是現在我的代碼不再將結果拆分爲基於消息表中的conversation_id的單獨表。 – Nathan1995
我修復它的劃痕!謝謝! – Nathan1995