如何申請在Oracle中加入要求的結果

Question

我有以下3個表：

SHIFT_MASTER,PATTERN_MASTER,PATTERN_DETAILS 

S_ID，P_ID，P_D_ID是SHIFT_MASTER，PATTERN_MASTER的priamry鍵，分別PATTERN_DETAILS表。

SHIFT_MASTER 

S_ID | S_NUMBER| S_Name 
---------------------------------  
1  A   MORNING 
2  B   AFTERNOON 
3  C   NIGHT 

PATTERN_MASTER 
P_ID | P_NAME 
---------------- 
1  Pattern 1 
2  Pattern 2  

PATTERN_DETAILS 
P_D_ID|P_ID | S_ID| ... 
---------------------  
1  1  1  
2  1  2  
3  1  3 
4  1  2  
5  1  1  
6  2  3 
7  2  2  
8  2  1  
9  2  3  

I GOT OUTPUT AS

P_ID | S_ID 
    1  1,2,3,2,1 
    2  3,2,1,3 

使用查詢

SELECT PATTERN_DETAILS.P_ID "PATTERN", 
    LISTAGG(PATTERN_DETAILS.S_ID, ', ') 
WITHIN GROUP (ORDER BY PATTERN_DETAILS.P_D_ID) "SHIFT" 
    FROM PATTERN_DETAILS 
    GROUP BY PATTERN_DETAILS.P_ID; 

我想是

P_NAME  | S_NUMBER 
Pattern 1 A,B,C,B,A 
Pattern 2 C,B,A,C 

任何建議???而不是P_ID我想顯示模式名稱，而不是移位ID我想顯示移位號碼。如何執行連接操作以及listagg函數？

Answer 1

你需要加入所有三個表得到這個，

SELECT pm.p_name "P_NAME", 
     listagg(sm.s_number, ', ') WITHIN GROUP (ORDER BY pd.p_d_id) "S_NUMBER" 
    FROM pattern_master pm, 
     pattern_details pd, 
     shift_master sm 
WHERE sm.s_id= pd.s_id 
    AND pm.p_id = pd.p_id 
GROUP BY pm.p_name;