循環打印通過兩個列表以獲得兩列固定每個列表

Question

假設我有這兩個列表中的每個元素的第一個字母之間的（自定義設置）空間：

column1 = ["soft","pregnant","tall"] 
column2 = ["skin","woman", "man"] 

如何循環打印通過這些兩個列表使用自定義的固定空間（例如，如10所示），從第一個列表的每個元素的第一個字母開始，直到第二個列表中的每個元素的第一個字母？的10的一組間隔的

輸出示例：

soft  skin 
pregnant woman 
tall  man 

Answer 1

與string formatting容易地完成，

column1 = ["soft","pregnant","tall"] 
column2 = ["skin","woman", "man"] 

for c1, c2 in zip(column1, column2): 
    print "%-9s %s" % (c1, c2) 

或者你可以使用str.ljust，這是整潔，如果你想有填充基於一個變量：

padding = 9 
for c1, c2 in zip(column1, column2): 
    print "%s %s" % (c1.ljust(padding), c2) 

（注：填充是9，而不是10因爲單詞之間的硬編碼空間）

Answer 2

column1 = ["soft","pregnant","tall"] 
column2 = ["skin","woman", "man"] 

for row in zip(column1, column2): 
    print "%-9s %s" % row # formatted to a width of 9 with one extra space after 

Answer 3

如何：

>>> column1 = ["soft","pregnant","tall"] 
>>> column2 = ["skin","woman", "man"] 
>>> for line in zip(column1, column2): 
...  print '{:10}{}'.format(*line) 
... 
soft  skin 
pregnant woman 
tall  man 

Answer 4

一個內膽採用新樣式的字符串格式化：

>>> column1 = ["soft", "pregnant", "tall"] 
>>> column2 = ["skin", "woman", "man"] 

>>> print "\n".join("{0}\t{1}".format(a, b) for a, b in zip(column1, column2)) 

soft  skin 
pregnant woman 
tall  man 

Answer 5

使用Python 3

column1 = ["soft","pregnant","tall"] 
column2 = ["skin","woman", "man"] 

for line in zip(column1, column2): 
    print('{:10}{}'.format(*line))