尋找每個球員的得分數

Question

我想添加他每個球員已經分配給他的得分項數量，並發現返回每個球員歸因於他的得分數量是有問題的。我的代碼如下，但我只是不能似乎得到了最後一關：

with open("players.dat") as f: 
    group = [] 
    for line in f: 
     fields = line.split() 
     group.append((fields[0], int(fields[1]))) 
     print(group) 

from collections import deque 

player_stats = {} 
with open("players.dat") as f: 
    for line in f: 
     name, score = line.split() 
     player_stats.setdefault(name, deque(maxlen=3)) 
     player_stats[name].append(int(score)) 

print(player_stats) 
print(len(score)) 

player_totals = {name: sum(scores) for name, scores in player_stats.items()} 
print(player_totals) 

player_totals = {name: max(scores) for name, scores in player_stats.items()} 
print(player_totals) 

player_totals = {name: min(scores) for name, scores in player_stats.items()} 
print(player_totals) 

#testing counting number of scores for each player 
#from collections import Counter 
#items = Counter(val[1] for val in player_stats.values()) 
#print(items) 

player_totals = {name:len(score)} 
print(player_totals) 

我的數據文件是：

rooney 12 
rooney 23 
rooney 56 
rooney 27 
ronaldo 14 
ronaldo 34 
messi 23 
messi 45 
messi 12 
messi 56 

我基本上是試圖找到每個球員的平均得分。

Answer 1

從collections.deque() documentation：

除了上述之外，雙端支持迭代，酸洗，len(d)，reversed(d)，copy.copy(d)，copy.deepcopy(d)，與in操作者會員資格測試，並且下標引用如d[-1]。

強調我的。

爲了得到長，只是len(scores)使用：

player_averages = {name: sum(scores)/len(scores) for name, scores in player_stats.items()}