如何使多個複選框搜索值的數據庫和

在同一頁

上顯示我不能顯示我的搜索表單，我懷疑問題是由於我不工作的複選框。我點擊搜索，它包含任何錯誤，但空白表。也許有可能是一些PHP和SQL語法錯誤，我忽略了。 FYI形式是的index.php如何使多個複選框搜索值的數據庫和

index.php 
<?php require_once('Connections/conn.php'); ?> 
<!DOCTYPE html> 
<html> 
<head> 
    <title>Casado</title> 
    <meta charset="utf-8"> 
    <meta name="viewport" content="width=device-width, initial-scale=1"> 
    <link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css"> 
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script> 
    <script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script> 
</head> 
<body> 

<nav class="navbar navbar-inverse"> 
    <div class="container-fluid"> 
    <div class="navbar-header"> 
     <button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#myNavbar"> 
     <span class="icon-bar"></span> 
     <span class="icon-bar"></span> 
     <span class="icon-bar"></span>       
     </button> 
     <a class="navbar-brand" href="/kahwin/index.php">Casado</a> 
    </div> 
    <div class="collapse navbar-collapse" id="myNavbar"> 
     <ul class="nav navbar-nav navbar-right"> 
     <li><a href="#"><span class="glyphicon glyphicon-log-in"></span> Login</a></li> 
     </ul> 
    </div> 
    </div> 
</nav> 

<div class="container text-center"> 
<div class="page-header"> 
<div class="container"> 

    <form method="post"> 
    <div class="form-group"> 
     <h3><label for="usr">Carian bajet anda:</label></h3> 
<div class= "col-md-12"> 
<div class=" col-md-4"></div> 

     <div class=" col-md-4"> 
     <input name="bajet" type="text" class="form-control" id="usr"></div> 

    </div> 
    <div class=" col-md-4"></div> 
    </div><br> 

    <h3><label for="sel1">Pilih negeri pilihan anda:</label></h3> 

    <div class= "col-md-12"> 
<div class=" col-md-4"></div> 

     <div class=" col-md-4"> 
      <select class="form-control" name="sel"> 
      <option>Kuala Lumpur</option> 
      <option>Negeri Sembilan</option> 
      <option>Pahang</option> 
      <option>Perak</option> 
      <option>Terengganu</option> 
      <option>Selangor</option> 

      </select> 
     </div> 

     <div class=" col-md-4"></div> 
    </div><br> 


     <br> 
     <h5><label for="check">Senarai Pra-perkahwinan:</label></h5> 
    <center> <div class="checkbox"> 
     <label class="checkbox-inline"> <input type="checkbox"name="check_list[]" value="Jurufoto"><label>Jurufoto</label></label> 
     <label class="checkbox-inline"> <input type="checkbox"name="check_list[]" value="Butik"><label>Butik</label></label> 
     <label class="checkbox-inline"> <input type="checkbox"name="check_list[]" value="Hiburan"><label>Hiburan</label></label> 
     <label class="checkbox-inline"> <input type="checkbox"name="check_list[]" value="Kad Kahwin"><label>Kad Kahwin</label></label> 
     <label class="checkbox-inline"> <input type="checkbox"name="check_list[]" value="Katering"><label>Katering</label></label> 
     <br> 


    </center> 
      <div class="col-md-4"></div> 

      <div class="col-md-4"> 
       <button class="btn btn-success btn-sm" name="search">Search&nbsp;<span class="glyphicon glyphicon-search"></span></button><br><br> 
      </div> 

      <div class="col-md-4"></div> 
     </div> 


</form> 
<table class="table table-bordered"> 
      <thead> 
       <tr> 

        <th>Jenis</th> 
        <th>Vendor</th> 
        <th>Negeri</th> 
        <th>No.</th> 
        <th>Pakej</th> 
        <th>Harga</th> 
        <th></th> 
       </tr> 
      </thead> 
      <tbody> 
      <?php 

       $budget = $_POST['bajet']; 
       $select = $_POST['sel']; 
       $check = $_POST['check_list']; 

       if (isset($_POST['search'])) { 
        mysql_select_db($database_conn, $conn); 



       $sql = mysql_query(" SELECT * 
       FROM vendor 
       RIGHT JOIN item 
       ON vendor.v_id=item.v_id 
       WHERE item.harga <= ' $budget ' 
       AND vendor.state = ' $select ' 
       AND vendor.type = ' $check '); 
       while($row = mysql_fetch_array($sql)) { 

      ?> 
      <tr> 

        <td><?php echo $row['type'] ?></td> 
        <td><?php echo $row['companyName'] ?></td> 
        <td><?php echo $row['state'] ?></td> 
        <td><?php echo $row['contact'] ?></td> 
        <td><?php echo $row['harga'] ?></td> 
        <td><?php echo $row['pakej'] ?></td> 
        <td><a href="index.php?v_id=<?php echo $row['v_id']?>">View Package</a></td> 


       </tr> 
       <?php } 
      } 
      ?> 
      </tbody> 
     </table> 
</div>

來源

2016-04-18 Tamimi Brewster

的HTML看起來雜亂無章，似乎有些標籤沒有被關閉，可能導致問題的 – kaklon

顯示在相同頁面（複選框）使用implode()爲複選框轉換成字符串選自複選框的陣列。

<?php 
$budget = $_POST['bajet']; 
$select = $_POST['sel']; 
$check = implode("','", $_POST['check_list']); 
$finalCheck = "'".$check ."'"; 

if (isset($_POST['search'])) { 
    mysql_select_db($database_conn, $conn); 

$sql = mysql_query(" SELECT * 
FROM vendor 
RIGHT JOIN item 
ON vendor.v_id=item.v_id 
WHERE item.harga <= '%". $bajet . "%' 
AND vendor.state = '%". $select ."%' 
AND vendor.type IN (". $finalCheck .")"); 
?>

來源

2016-04-18 08:03:47 RJParikh

我得到錯誤警告：破滅（）：用C傳遞的參數無效：\的appserv \ WWW \卡薩多\的index.php在線111 警告：mysql_fetch_array（）期望參數1是資源，布爾線125給出的C：\ AppServ \ www \ casado \ index.php @ ruchish-parikh –

print_r（$ _ POST ['check_list']）並檢查它的數組或不。 – RJParikh

它從警告 –

如何使多個複選框搜索值的數據庫和

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