Python：程序在資源管理器中打開不正確的文件路徑？

Question

我試圖讓我的程序打開用戶輸入的文件路徑。此條目保存在我的data [0]列表中，然後使用os.system函數調用。而不是打開保存的文件路徑，瀏覽器打開並將我帶到「我的文檔」。 1.爲什麼會發生這種情況？2.如何更改此設置讓瀏覽器打開保存的用戶數據？

import Tkinter as tk 
import pickle 
import os 


data = [] 

class MyPath(tk.Frame): 


def __init__(self, parent): 
    tk.Frame.__init__(self, parent) 
    self.parent = parent 
    self.pack() 
    MyPath.make_widgets(self) 

def make_widgets(self): 
    self.parent.title("MyPath") 

    #self.textbox = Text(root) 
    #self.textbox.pack() 

    # create a prompt, an input box, an output label, 
    # and a button to do the computation 
    self.prompt = tk.Label(self, text="Enter your Filepath:", anchor="w") 
    self.textbox = tk.Text(self) 
    self.entry = tk.Entry(self) 
    self.open = tk.Button(self, text="Open", command = self.open) 
    self.view = tk.Button(self, text="View", command = self.view) 
    self.submit = tk.Button(self, text="Save", command = self.save) 
    self.output = tk.Label(self, text="") 
    self.clear_button = tk.Button(self, text="Clear text", command=self.clear_text) 

    # lay the widgets out on the screen. 
    self.prompt.pack(side="top", fill="x") 
    self.entry.pack(side="top", fill="x", padx=20) 
    self.output.pack(side="top", fill="x", expand=True) 
    self.textbox.pack(side="top", fill="x") 
    self.view.pack(side="bottom") 
    self.submit.pack(side="bottom") 
    self.clear_button.pack(side="bottom") 
    self.open.pack(side="top") 


def clear_text(self): 
    self.entry.delete(0, 'end') 
    self.textbox.delete(1.0, 'end') 


def save(self): 
    # get the value from the input widget 

    try: 
     a = self.entry.get() 
     result = data.append(self.entry.get()) 

    except ValueError: 
     result = "Please enter filepaths only" 

    #saves list to pickle file 
    #pickle.dump(data, open("save.p", "wb")) 

    # set the output widget to have our result 
    self.output.configure(text=result) 
    print (data) 

def view(self): 
    pickle.load(open("save.p", "rb")) 
    self.textbox.insert("1.0", str(pickle.load(open("save.p", "rb")))) 
    print pickle.load(open("save.p", "rb")) 

def open(self): 
    #src = "/Users/matt/Documents/Python/MyApp.py" 
    dst = data 
    #path = pickle.load(open("save.p", "rb")) 
    os.system('Explorer "data[0]"') 

if __name__ == "__main__": 
    root = tk.Tk() 
    MyPath(root).pack(fill="both", expand=True) 
    root.mainloop() 

任何幫助非常感謝！

Answer 1

os.system('Explorer "%s"' % data[0]) 

導致你到底字符串看起來像「資源管理器數據[0]」當Explorer找不到數據[0]其恢復爲默認位置，用戶的路徑 - 我的文檔