這個select語句的正確sql腳本是什麼？

Question

這是我的腳本

SELECT iBranch_num, 
    CASE WHEN iPatient_typ=1 THEN COUNT(iPatient_num) ELSE 0 END AS [New Patient], 
    CASE WHEN iPatient_typ=2 THEN COUNT(iPatient_num) ELSE 0 END AS [Buying Patient],     
    CASE WHEN iPatient_typ=3 THEN COUNT(iPatient_num) ELSE 0 END AS [Active Patient], 
    CASE WHEN iPatient_typ=4 THEN COUNT(iPatient_num) ELSE 0 END AS [Inactive Patient] 
FROM tblsotransaction 
WHERE iStatus_typ=1 
    AND iApply_dt BETWEEN 20130401 AND 20130408 
    AND iBranch_num=14 
GROUP BY iBranch_num, iPatient_typ 

當前結果：

14, 25, 0, 0, 0 
14, 0, 8, 0, 0 
14, 0, 0, 97, 0 
14, 0, 0, 0, 2 

我想要的結果是這樣

14, 25, 8, 9, 2 

Answer 1

裹聚合函數COUNT裏面全CASE表達，從GROUP BY子句刪除iPatient_typ：

SELECT 
    iBranch_num, 
    COUNT(CASE WHEN iPatient_typ=1 THEN iPatient_num ELSE 0 END) AS [New Patient], 
    COUNT(CASE WHEN iPatient_typ=2 THEN iPatient_num ELSE 0 END) AS [Buying Patient],     
    COUNT(CASE WHEN iPatient_typ=3 THEN iPatient_num ELSE 0 END) AS [Active Patient], 
    COUNT(CASE WHEN iPatient_typ=4 THEN iPatient_num ELSE 0 END) AS [Inactive Patient] 
FROM tblsotransaction 
WHERE iStatus_typ = 1 
    AND iApply_dt BETWEEN 20130401 AND 20130408 
    AND iBranch_num = 14 
GROUP BY iBranch_num; 

或者：SUM：

SELECT 
    iBranch_num, 
    SUM(CASE WHEN iPatient_typ = 1 THEN 1 ELSE 0 END) AS [New Patient], 
    SUM(CASE WHEN iPatient_typ = 2 THEN 1 ELSE 0 END) AS [Buying Patient], 
    SUM(CASE WHEN iPatient_typ = 3 THEN 1 ELSE 0 END) AS [Active Patient], 
    SUM(CASE WHEN iPatient_typ = 4 THEN 1 ELSE 0 END) AS [Inactive Patient] 
FROM tblsotransaction 
WHERE iStatus_typ = 1 
    AND iApply_dt BETWEEN 20130401 AND 20130408 
    AND iBranch_num = 14 
GROUP BY iBranch_num;