如何用字母創建按字母順序排列的列表？

Question

大家好我想實現阿爾法下令列

名單上picture

如圖但是我的算法是不明確的，也許有人可以幫助我內

string[] letters = new string[] { "A", "B", "C", "D", "E", "F", "G", "H", "I", 
    "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", 
    "Y", "Z", "Å", "Ä", "Ö", "0-9" }; 

int j = 0, s = 0, i = 1; 
var fullServices = (from se in EntityBase.db.Services 
       orderby se.Name 
       select se).ToList(); 
int total = fullServices.Count; 
var grouped = (from l in letters 
      select new ServiceInfo 
      { 
       Letter = l, 
       Services = EntityBase.db.Services.Where(se => se.Name.StartsWith(l)).ToList(), 
       Total = EntityBase.db.Services.Where(se => se.Name.StartsWith(l)).Count() 
      }).ToList(); 
Dictionary<int, List<ServiceInfo>> result = new Dictionary<int, List<ServiceInfo>>(); 

changecell: 

List<ServiceInfo> item = new List<ServiceInfo>(); 
while (j < letters.Count()) 
{ 
letterchange: 
    List<Service> _services = new List<Service>(); 
    while (s < total) 
    { 
     if ((s == (5 + (total % 5 > i ? 1 : 0)) * i)) 
     { 
     item.Add(new ServiceInfo() { Letter = letters[j], Services = _services }); 
     result.Add(i, item); 
     if (i == 6) 
      goto exit; 
     i++; 
     goto changecell; 
     } 
     //start render services 
     if (fullServices.ElementAt(s).Name.StartsWith(letters[j])) 
     { 
     _services.Add(fullServices.ElementAt(s)); 
     s++;//increment service in list 
     } 
     else //letter switch 
     { 
     item.Add(new ServiceInfo() { Letter = letters[j], Services = _services }); 
     j++; 
     goto letterchange; 
     } 
    }//end render services 

} 
exit: 
return View(result); 

在結果我代碼我看到錯過的字母XYZÅÄÖ ，它看起來像this

這裏是代碼，呈現字典

<% foreach (KeyValuePair<int, List<BL.Models.Infos.ServiceInfo>> col in Model) 
{ %> 
    <ul class="col"> 
    <% foreach (var item in col.Value) 
{ %> 
    <% if (!item.Services.Any()) 
{%> 
    <li class="disabled"> 
     <h1> 
     <%= item.Letter %></h1> 
    </li> 
    <%} 
else 
{ %> 
    <li> 
     <h1> 
     <a href="/service/info/<%= item.Letter %>"><%= item.Letter %></a> 
     </h1> 
    </li> 
    <% foreach (var service in item.Services) 
{ %> 
    <li><a href="/service/info/<%= service.Name %>"><%= service.Name %></a></li> 
    <%} 
} 
}%> 
    </ul> 
    <%} %> 

請幫助...

Answer 1

嗯，你肯定是正確的，代碼不是特別清楚:)

我真的不按照你的代碼的主循環，但這裏的一個更簡單的起點。請注意，它不會正確分組0-9（目前只處理0）：說實話，我不確定最佳方法。你可能希望把他們關閉，直到你得到不匹配任何正常的字母一些條目...

using System; 
using System.Linq; 

class Test 
{ 
    static void Main(string[] args) 
    { 
     ShowGroups(); 
    } 

    private static readonly char[] Letters = 
     "ABCDEFGHIJKLMNOPQRSTUVWXYZÅÄÖ0".ToCharArray(); 

    // This is taking the place of EntityBase.db.Services 
    // for the purposes of the test program 
    public static string[] Services = { "Blogger", "Delicious", 
      "Digg", "Ebay", "Facebook", "Feed", "Flickr", 
      "Friendfeed", "Friendster", "Furl", "Google", 
      "Gosupermodel", "Lastfm", "Linkedin", "Livejournal", 
      "Magnolia", "Mixx", "Myspace", "NetOnBuy", "Netvibes", 
      "Newsvine", "Picasa", "Pownce", "Reddit", "Stumbleupon", 
      "Technorati", "Twitter", "Vimeo", "Webshots", 
      "Wordpress" }; 

    public static void ShowGroups() 
    { 
     var groupedByLetter = 
      from letter in Letters 
      join service in Services on letter equals service[0] into grouped 
      select new { Letter = letter, Services = grouped }; 

     // Demo of how to access the groups 
     foreach (var entry in groupedByLetter) 
     { 
      Console.WriteLine("=== {0} ===", entry.Letter); 
      foreach (var service in entry.Services) 
      { 
       Console.WriteLine (" {0}", service); 
      } 
      Console.WriteLine(); 
     } 
    } 
} 

我不知道你是怎麼打算，雖然拆分結果納入5個等於列。 ..

Answer 2

這可能是離開了 - 我剛剛在記事本中完成了這項工作（現在無法訪問IDE）。它看起來像你試圖填充Dictionary<int, List<ServiceInfo>> result實例，我假設你的View方法理解如何在列中佈局結果。

這裏所說：

string[] letters = new string[] { "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", 
            "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", 
            "U", "V", "W", "X", "Y", "Z", "Å", "Ä", "Ö", "0-9" }; 

var result = new Dictionary<int, List<ServiceInfo>>(); 
foreach (var letter in letters) 
{ 
    var services = (from se in EntityBase.db.Services 
        where se.Name.StartsWith(letter) 
        orderby se.Name 
        select select new ServiceInfo 
        { 
         Letter = letter, 
         Services = EntityBase.db.Services.Where(se => se.Name.StartsWith(letter)).ToList(), 
         Total = EntityBase.db.Services.Where(se => se.Name.StartsWith(letter)).Count() 
        }).ToList(); 
    result.Add(i, services); 
} 

如果這是正確的，它可能不會是最快的實現，但它更具有可讀性。