如何按字母順序排列NSArray？

Question

如何將填入[UIFont familyNames]的數組按字母順序排序？

Answer 1

最簡單的方法是，提供一種選擇（Apple's documentation的詳細信息）

目標C

sortedArray = [anArray sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)]; 

夫特

let descriptor: NSSortDescriptor = NSSortDescriptor(key: "YourKey", ascending: true, selector: "localizedCaseInsensitiveCompare:") 
let sortedResults: NSArray = temparray.sortedArrayUsingDescriptors([descriptor]) 

---

蘋果提供了幾種選擇器字母排序：

• compare:
• caseInsensitiveCompare:
• localizedCompare:
• localizedCaseInsensitiveCompare:
• localizedStandardCompare:

夫特

var students = ["Kofi", "Abena", "Peter", "Kweku", "Akosua"] 
students.sort() 
print(students) 
// Prints "["Abena", "Akosua", "Kofi", "Kweku", "Peter"]" 

Reference

Answer 2

這裏提供的其他的答案提及使用@selector（localizedCaseInsensitiveCompare :) 本作的NSString數組的偉大工程，但是如果你想要將其擴展到其他類型的對象，和排序這些對象根據「名稱」屬性，您應該這樣做：

NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"name" ascending:YES]; 
sortedArray=[anArray sortedArrayUsingDescriptors:@[sort]]; 

您的對象將根據這些對象的name屬性進行排序。

如果你想排序是不區分大小寫，您將需要設置描述這樣

NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"name" ascending:YES selector:@selector(caseInsensitiveCompare:)]; 

Answer 3

排序的NSString的列表中使用的東西像NSNumericSearch的更強大的方法：

NSArray *sortedArrayOfString = [arrayOfString sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) { 
      return [(NSString *)obj1 compare:(NSString *)obj2 options:NSNumericSearch]; 
     }]; 

與SortDescriptor相結合，即會看到這樣的：

NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"name" ascending:YES comparator:^NSComparisonResult(id obj1, id obj2) { 
     return [(NSString *)obj1 compare:(NSString *)obj2 options:NSNumericSearch]; 
    }]; 
NSArray *sortedArray = [anArray sortedArrayUsingDescriptors:[NSArray arrayWithObject:sort]]; 

Answer 4

-(IBAction)SegmentbtnCLK:(id)sender 
{ [self sortArryofDictionary]; 
    [self.objtable reloadData];} 
-(void)sortArryofDictionary 
{ NSSortDescriptor *sorter; 
    switch (sortcontrol.selectedSegmentIndex) 
    {case 0: 
      sorter=[[NSSortDescriptor alloc]initWithKey:@"Name" ascending:YES]; 
      break; 
     case 1: 
      sorter=[[NSSortDescriptor alloc]initWithKey:@"Age" ascending:YES]; 
      default: 
      break; } 
    NSArray *sortdiscriptor=[[NSArray alloc]initWithObjects:sorter, nil]; 
    [arr sortUsingDescriptors:sortdiscriptor]; 
    } 

Answer 5

使用以下代碼以字母順序排序：

NSArray *unsortedStrings = @[@"Verdana", @"MS San Serif", @"Times New Roman",@"Chalkduster",@"Impact"]; 

    NSArray *sortedStrings = 
    [unsortedStrings sortedArrayUsingSelector:@selector(compare:)]; 

    NSLog(@"Unsorted Array : %@",unsortedStrings);   
    NSLog(@"Sorted Array : %@",sortedStrings); 

下面是控制檯日誌：

2015-04-02 16:17:50.614 ToDoList[2133:100512] Unsorted Array : (
    Verdana, 
    "MS San Serif", 
    "Times New Roman", 
    Chalkduster, 
    Impact 
) 

2015-04-02 16:17:50.615 ToDoList[2133:100512] Sorted Array : (
    Chalkduster, 
    Impact, 
    "MS San Serif", 
    "Times New Roman", 
    Verdana 
) 

Answer 6

另一種簡單的方法進行排序字符串數組由通過使用的NSString description屬性這種方式：

NSSortDescriptor *valueDescriptor = [NSSortDescriptor sortDescriptorWithKey:@"description" ascending:YES]; 
    arrayOfSortedStrings = [arrayOfNotSortedStrings sortedArrayUsingDescriptors:@[valueDescriptor]]; 

Answer 7

這已經有很好的答案ose，但我會加我的更具體。

在英語中，通常當我們字母化時，我們忽略短語開頭的單詞「the」。所以「美國」將在「U」而不是「T」下訂購。

這是爲你做的。

這可能是最好把這些分類。

// Sort an array of NSStrings alphabetically, ignoring the word "the" at the beginning of a string. 

-(NSArray*) sortArrayAlphabeticallyIgnoringThes:(NSArray*) unsortedArray { 

    NSArray * sortedArray = [unsortedArray sortedArrayUsingComparator:^NSComparisonResult(NSString* a, NSString* b) { 

     //find the strings that will actually be compared for alphabetical ordering 
     NSString* firstStringToCompare = [self stringByRemovingPrecedingThe:a]; 
     NSString* secondStringToCompare = [self stringByRemovingPrecedingThe:b]; 

     return [firstStringToCompare compare:secondStringToCompare]; 
    }]; 
    return sortedArray; 
} 

// Remove "the"s, also removes preceding white spaces that are left as a result. Assumes no preceding whitespaces to start with. nb: Trailing white spaces will be deleted too. 

-(NSString*) stringByRemovingPrecedingThe:(NSString*) originalString { 
    NSString* result; 
    if ([[originalString substringToIndex:3].lowercaseString isEqualToString:@"the"]) { 
     result = [[originalString substringFromIndex:3] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]; 
    } 
    else { 
     result = originalString; 
    } 
    return result; 
}