我有以下查詢：SQL逗號分隔一行Group By子句
SELECT
Account,
Unit,
SUM(state_fee),
Code
FROM tblMta
WHERE MTA.Id = '123'
GROUP BY Account,Unit
這當然會拋出一個異常，因爲代碼不是group by子句。每個state_fee都有一個代碼。我如何獲得此代碼以1條記錄顯示（每個state_fee每個state_fee 1個代碼）作爲逗號分隔列表？我在這裏看到了不同的解決方案，但我找不到任何與group by合作的解決方案。
你想用FOR XML PATH結構：
SELECT ACCOUNT,
unit,
SUM(state_fee),
Stuff((SELECT ', ' + code
FROM tblmta t2
WHERE t2.ACCOUNT = t1.ACCOUNT
AND t2.unit = t1.unit
AND t2.id = '123'
FOR XML PATH('')), 1, 2, '') [Codes]
FROM tblmta t1
WHERE t1.id = '123'
GROUP BY ACCOUNT,
unit
見其他例子在這裏：
有沒有內置聚合函數來連接，但這篇文章討論了幾種可供選擇的解決方案，包括用戶自定義串連聚合函數：
https://www.simple-talk.com/sql/t-sql-programming/concatenating-row-values-in-transact-sql/
這將顯示錶，索引名，索引類型，索引列，並列入列：
with [indexes] (table_name, index_name, column_name, index_id, key_ordinal, object_id, type_desc)
as(
SELECT distinct
T.[name] AS [table_name], I.[name] AS [index_name],
AC.[name] AS [column_name],
I.[index_id], IC.[key_ordinal], T.[object_id], i.type_desc
FROM sys.[tables] AS T
INNER JOIN sys.[indexes] I ON T.[object_id] = I.[object_id]
INNER JOIN sys.[index_columns] IC ON I.[object_id] = IC.[object_id] and IC.index_id=I.index_id
LEFT OUTER JOIN sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id]
WHERE T.[is_ms_shipped] = 0 AND I.[type_desc] <> 'HEAP'
)
select
distinct
db_name() as dbname,
type_desc,
table_name,
index_name,
column_name,
STUFF((
select ', ' + column_name
from [indexes] t2
where t1.table_name=t2.table_name and t1.[index_name]=t2.[index_name] and t2.[key_ordinal] = 0
for xml path('')), 1, 2, '') inc_cols
from [indexes] t1
where t1.[key_ordinal] = 1
GROUP BY table_name, index_name, type_desc, column_name
首先我想projectdms只是擦傷文章原始W/o歸屬地，但實際上該網站屬於文章作者 –
該鏈接已經死亡。這是一個替代方案：https://www.simple-talk.com/sql/t-sql-programming/concatenating-row-values-in-transact-sql/ – gpinkas