如何應對不確定的恆定誤差

Question

我不知道我可以處理這個錯誤即時得到我的代碼

Notice: Use of undefined constant result2 - assumed 'result2' in C:\xampp\htdocs\how are things\admin panel\register3.php on line 62 

上線62的代碼是

$result2 = mysql_query("INSERT INTO users (id ,username, user_level, type, first_name, last_name, email, password, phone_number) VALUES('','$username', '2', 'a','$first_name', '$last_name', '$email','$password','$phone_number') ") or die(mysql_error()); 

這個代碼在找到它的

if (empty($error)){ 
    $result = mysql_query("SELECT * FROM users WHERE email='$email' OR username='$username' ") or die(mysql_error()); 
    $result2 = mysql_query("INSERT INTO users (id ,username, user_level, type, first_name, last_name, email, password, phone_number) VALUES('','$username', '2', 'a','$first_name', '$last_name', '$email','$password','$phone_number') ") or die(mysql_error()); 
    if(!result2){ 
     die('Could not insert into the database: '.mysql_error()); 
    } 

    } else{ 
    $error_message = '<span class="error">'; 
    foreach($error as $key => $Values){ 
    $error_message.= "$Values"; 

    } 
    $error_message.="</span><br/><br/>"; 

    } 

Answer 1

if(!result2){ 

你在那裏錯過了$。請使用IDE來編碼，這樣可以避免這種錯誤