如何在Zend Framework中以JSON格式返回Application_Model 1.11

Question

我在我的視圖中定義了一個名爲Student的變量。在我看來，如何將Student對象顯示爲JSON？

public function previewAction() 
{ 
    // ... 
    $this->view->student = $student; 
} 

在我preview.phtml觀，我有以下幾點：

<script> 
    // this doesn't return the Application_Model as a JSON object in the html  
    var studentData = <?php echo Zend_Json::encode($this->student); ?>; 
</script> 

Answer 1

圍繞PHP標籤

<script> 
    // this doesn't return the Application_Model as a JSON object in the html  
    var studentData = "<?php echo Zend_Json::encode($this->student); ?>"; 
</script>