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此代碼以1%到2%(每秒總共6 GB)的速度吞噬我的內存。 誰能告訴我什麼是錯的?提前致謝。我是新手,所以如果我聽起來像一個完全白癡,我是。我想快速回答。捕獲位圖快速進食內存
#include <windows.h>
#include <iostream>
#include <stdio.h>
using namespace std;
/* Globals */
int ScreenX = 0;
int ScreenY = 0;
BYTE* ScreenData = 0;
void ScreenCap()
{
HDC hScreen = GetDC(GetDesktopWindow());
//hScreen2 = hScreen;
if (ScreenX == 0)
{
ScreenX = GetDeviceCaps(hScreen, HORZRES);
ScreenY = GetDeviceCaps(hScreen, VERTRES);
}
HDC hdcMem = CreateCompatibleDC (hScreen);
HBITMAP hBitmap = CreateCompatibleBitmap(hScreen, ScreenX, ScreenY);
HGDIOBJ hOld = SelectObject(hdcMem, hBitmap);
BitBlt(hdcMem, 0, 0, ScreenX, ScreenY, hScreen, 0, 0, SRCCOPY);
SelectObject(hdcMem, hOld);
BITMAPINFOHEADER bmi = {0};
bmi.biSize = sizeof(BITMAPINFOHEADER);
bmi.biPlanes = 1;
bmi.biBitCount = 32;
bmi.biWidth = ScreenX;
bmi.biHeight = -ScreenY;
bmi.biCompression = BI_RGB;
bmi.biSizeImage = 0;// 3 * ScreenX * ScreenY;
if(ScreenData)
free(ScreenData);
ScreenData = (BYTE*)malloc(4 * ScreenX * ScreenY);
GetDIBits(hdcMem, hBitmap, 0, ScreenY, ScreenData, (BITMAPINFO*)&bmi, DIB_RGB_COLORS);
ReleaseDC(GetDesktopWindow(),hScreen);
DeleteDC(hdcMem);
}
inline int PosB(int x, int y)
{
return ScreenData[4*((y*ScreenX)+x)];
}
inline int PosG(int x, int y)
{
return ScreenData[4*((y*ScreenX)+x)+1];
}
inline int PosR(int x, int y)
{
return ScreenData[4*((y*ScreenX)+x)+2];
}
bool ButtonPress(int Key)
{
bool button_pressed = false;
while(GetAsyncKeyState(Key))
button_pressed = true;
return button_pressed;
}
int main()
{
while (true)
{
ScreenCap();
/*for (int x = 1; x < ScreenX; x++)
{
for (int y = 1; y < ScreenY; y++)
{
int Red = PosR(x, y);
int Green = PosG(x, y);
int Blue = PosB(x, y);
if (Red == 22 && Green == 58 && Blue == 89)
{
cout << ">:D";
POINT pos;
GetCursorPos(&pos);
int DX = 683 - x;
int DY = 683 - y;
/*COLORREF col = GetPixel(hScreen2, DX - pos.x + 1, pos.y - DY + 1);
int red = GetRValue(col);
int blue = GetBValue(col);
int green = GetGValue(col);
if (red == 22 && green == 58 && blue == 89)
{
break;
}
//SetCursorPos(x + DX, y + DY);
SetCursorPos(DX - pos.x + 1, pos.y - DY + 1);
cout << DX - pos.x << ", " << pos.y - DY + 1 << endl;
break;
}
}
}*/
}
system("PAUSE");
return 0;
}
那麼我會如何刪除它們?就像我說的,我是個白癡。 – user3103398
我討厭問,但這是我最後的問題(我希望)。你可以發佈修改後的版本嗎?我希望沒有太多要求。 – user3103398
'CreateCompatibleBitmap'的文檔應該指向'DeleteObject',它是位圖刪除功能。 MSDN上沒有示例嗎? –