SQL遞歸匹配具有多個值

Question

我有一個這樣的表（這是簡化的）

 
ID | FOO | BAR 
-------------- 
1 | 100 | 200 
1 | 101 | 202 
1 | 102 | 205 
2 | 100 | 200 
2 | 101 | 222 
2 | 102 | 203 
3 | 100 | 201 
3 | 101 | 202 
3 | 102 | 204 
4 | 100 | 201 
4 | 101 | 202 
4 | 102 | 205 

如果我查詢FOO =返回100和BAR = 200名的ID爲1和2這是所有精細。

我希望能夠做的就是FOO = 100和BAR = 200然後FOO = 101和BAR = 202所以我只得到返回ID = 1

，如果我做了FOO = 100和BAR = 201和FOO = 101和BAR = 202和FOO = 102和BAR = 205我將只被返回ID 4

如果我沒有FOO = 100和BAR = 201我會看到ID 3和4

我認爲我應該能夠做到這一點遞歸_CTE類似Recurisve query in SQL Server但我不能讓我頭像如何構造它。

是FOO可以去太水平不限於3它只是被簡化，這個例子

Answer 1

如果我正確理解，你需要共同的ID的每個條件。這裏

with the_table(ID, FOO, BAR) as(
select 1 , 100 , 200 union all 
select 1 , 101 , 202 union all 
select 1 , 102 , 205 union all 
select 2 , 100 , 200 union all 
select 2 , 101 , 222 union all 
select 2 , 102 , 203 union all 
select 3 , 100 , 201 union all 
select 3 , 101 , 202 union all 
select 3 , 102 , 204 union all 
select 4 , 100 , 201 union all 
select 4 , 101 , 202 union all 
select 4 , 102 , 205 
) 


select id from the_table 
where 
(FOO = 100 and BAR = 201) or 
(FOO = 101 AND BAR = 202) or 
(FOO = 102 and BAR = 205) 
group by id 
having count(*) = 3 

注：

如果是這樣，如果FOO, BAR是每ID唯一的，那麼你就可以做到這一點count(*) = 3，數3是條件計數where條款，例如，如果你有隻是一個條件(FOO = 100 and BAR = 201)，然後查詢是：

select id from the_table 
where 
(FOO = 100 and BAR = 201) 
group by id 
having count(*) = 1 

Answer 2

無需遞歸CTE。對於FOO = 100和BAR = 200，然後FOO = 101和BAR = 202，你可以這樣做。

with cte 
as 
(

SELECT ID,FOO,BAR 
FROM TAB 
WHERE FOO = 100 and BAR = 200 
) 
SELECT ID 
FROM cte 
WHERE FOO=101 and BAR = 202 

對於FOO = 100和BAR = 201和FOO = 101和BAR = 202和FOO = 102和BAR = 205，則可以做到這一點：

with cte 
    as 
    (

    SELECT ID,FOO,BAR 
    FROM TAB 
    WHERE FOO = 100 and BAR = 201 
    ) 
    SELECT ID 
    FROM 
    (SELECT ID,FOO,BAR 
    FROM cte 
    WHERE FOO=101 and BAR = 202 
    ) result(ID,FOO,BAR) 
    WHERE FOO=102 and BAR = 205