SQL審覈日誌運行總計

Question

我一個表的審計日誌：

BugId  Timestamp    Status 
1   2010-06-24 10:00:00  open 
2   2010-06-24 11:00:00  open 
1   2010-06-25 12:00:00  closed 
2   2010-06-26 13:00:00  closed 

我想的運行總計打開和關閉的錯誤，如：

Timestamp   #  Status 
2010-06-25 00:00:00 2  open 
2010-06-26 00:00:00 1  open 
2010-06-26 00:00:00 1  closed 
2010-06-27 00:00:00 2  closed 

我怎麼可能做到這一點查詢（或類似）在Microsoft SQL Server 2000中？

輸出旨在用於提供時間序列圖表，因此我不在乎是否存在具有0個輸出的行，因爲我可能只會選擇上個月的時間範圍。

Answer 1

我認爲實際上輸出樣本數據相符：在25日（上午12點），有兩個開放的錯誤。 26日，有一個開放的bug，一個關閉。到了27日，所有的錯誤都關閉了。

目前尚不清楚應如何創建主日期。就我的例子而言，我預先加載了我知道的正確日期，但這可以根據用戶的要求以各種方式完成。

無論如何，代碼如下。這應該適用於在同一天打開和關閉多次錯誤的情況。它假定一個bug不能同時打開和關閉。

/** Setup the tables **/ 
IF OBJECT_ID('tempdb..#bugs') IS NOT NULL DROP TABLE #bugs 

CREATE TABLE #bugs (
    BugID INT, 
    [Timestamp] DATETIME, 
    [Status] VARCHAR(10) 
) 

IF OBJECT_ID('tempdb..#dates') IS NOT NULL DROP TABLE #dates 

CREATE TABLE #dates ( 
    [Date] DATETIME 
) 

/** Load the sample data. **/ 
INSERT #bugs 
SELECT 1, '2010-06-24 10:00:00', 'open' UNION ALL 
SELECT 2, '2010-06-24 11:00:00', 'open' UNION ALL 
SELECT 1, '2010-06-25 12:00:00', 'closed' UNION ALL 
SELECT 2, '2010-06-26 13:00:00', 'closed' 

/** Build an arbitrary date table **/ 
INSERT #dates 
SELECT '2010-06-24' UNION ALL 
SELECT '2010-06-25' UNION ALL 
SELECT '2010-06-26' UNION ALL 
SELECT '2010-06-27' 


/** 
Subquery x: 
For each date in the #date table, 
get the BugID and it's last status. 
This is for BugIDs that have been 
opened and closed on the same day. 

Subquery y: 
Drawing from subquery x, get the 
date, BugID, and Status of its 
last status for that day 

Main query: 
For each date, get the count 
of the most recent statuses for 
that date. This will give the 
running totals of open and 
closed bugs for each date 
**/ 
SELECT 
    [Date], 
    COUNT(*) AS [#], 
    [Status] 
FROM (
    SELECT 
    Date, 
    x.BugID, 
    b.[Status] 
    FROM ( 
    SELECT 
     [Date], 
     BugID, 
     MAX([Timestamp]) AS LastStatus 
    FROM #dates d 
    INNER JOIN #bugs b 
    ON d.[Date] > b.[Timestamp] 
    GROUP BY 
     [Date], 
     BugID 
    ) x 
    INNER JOIN #bugs b 
    ON x.BugID = b.BugID 
    AND x.LastStatus = b.[Timestamp] 
) y 
GROUP BY [Date], [Status] 
ORDER BY [Date], CASE WHEN [Status] = 'Open' THEN 1 ELSE 2 END 

結果：

Date     #   Status 
----------------------- ----------- ---------- 
2010-06-25 00:00:00.000 2   open 
2010-06-26 00:00:00.000 1   open 
2010-06-26 00:00:00.000 1   closed 
2010-06-27 00:00:00.000 2   closed 

Answer 2

use tempdb 
go 
create table audit_log 
(
BugID integer not null 
, dt_entered_utc datetime not null default (getutcdate()) 
, [status] varchar(10) not null 
); 


INSERT INTO audit_log (BugID, dt_entered_utc, [status]) VALUES (1, '2010-06-24 10:00', 'open'); 
INSERT INTO audit_log (BugID, dt_entered_utc, [status]) VALUES (2, '2010-06-24 11:00', 'open'); 
INSERT INTO audit_log (BugID, dt_entered_utc, [status]) VALUES (1, '2010-06-25 12:00', 'closed'); 
INSERT INTO audit_log (BugID, dt_entered_utc, [status]) VALUES (2, '2010-06-26 13:00', 'closed'); 

SELECT 
    [Date] = CAST (CONVERT (varchar, a.dt_entered_utc, 101) as datetime) 
    , [#] = COUNT (1) 
    , [Status] = a.status 
FROM audit_log a 
GROUP BY CAST (CONVERT (varchar, a.dt_entered_utc, 101) as datetime), a.status 
ORDER by [Date] ASC 

 
Date       #  Status 
2010-06-24 00:00:00.000  2  open 
2010-06-25 00:00:00.000  1  closed 
2010-06-26 00:00:00.000  1  closed