如何根據另一個多維數組數據結果搜索多維數組數據

Question

我有2個多維數組，它從數據庫中的2個不同表中獲取數據。其中一人有3支球隊，另一支球隊有球隊的命令。

$sql = "select id, supervizori, grupi, tipo_crt, operatori, data, status, nome, cognome, cel, codice_fiscale from kontrata"; 
    $result = mysqli_query($dbCon, $sql); 
    if(!$sql) { 
     die("Error1"); 
    } //this query takes the orders from the kontrata table. 

$sql_2 = "select * from grupi"; 
$result_2 = mysqli_query($dbCon, $sql_2); 
    if(!$sql_2) { 
     die("Error2"); 
    } // this query take the teams from the grupi table. 

while ($row = mysqli_fetch_assoc($result)) {    
     $kontratat[$row['id']]['supervizori'] = $row['supervizori']; 
     $kontratat[$row['id']]['grupi'] = $row['grupi']; 
     $kontratat[$row['id']]['tipo_crt'] = $row['tipo_crt']; 
     $kontratat[$row['id']]['operatori'] = $row['operatori']; 
     $kontratat[$row['id']]['data'] = $row['data']; 
     $kontratat[$row['id']]['status'] = $row['status']; 
     $kontratat[$row['id']]['nome'] = $row['nome']; 
     $kontratat[$row['id']]['cognome'] = $row['cognome']; 
     $kontratat[$row['id']]['cel'] = $row['cel']; 
     $kontratat[$row['id']]['codice_fiscale'] = row['codice_fiscale']; 
} // In this loop i take the data according to the order table. 

while ($row = mysqli_fetch_assoc($result_2)) {  
    $kontratat_2[$kontratat['id']]['grup_name'] = $row['grup_name']; 
} // In this loop i take the teams. 

我使用的foreach的數據dispay到一個表，但是當我打電話的foreach導致我得到的所有訂單（這是正常的），但我有100個訂單 那些3支球隊有使循環後。我想用secont循環過濾每個團隊的訂單。簡單地說，我可以用第一個查詢中的「ID」查看每個團隊的所有訂單，而不是將同一個團隊展示50次。謝謝:)

Array 
(
    [11] => Array 
     (
     [supervizori] => data 
     [grupi] => Doctors //this is the team 
     [tipo_crt] => LUCE 
     [operatori] => data 
     [data] => 2015-12-20 
     [status] => OK 
     [nome] => data 
     [cognome] => data 
     [cel] => data 
     [codice_fiscale] => shkrfl93a08a123a 
    ) 

[12] => Array 
    (
     [supervizori] => data 
     [grupi] => BMW //this is the team 
     [tipo_crt] => data 
     [operatori] => data 
     [data] => 2015-12-22 
     [status] => KO 
     [nome] => rgrg 
     [cognome] => grdgdrgdrg 
     [cel] => serges 
     [codice_fiscale] => a 
    ) 

[17] => Array 
    (
     [supervizori] => data 
     [grupi] => Doctors //this is the team  
     [tipo_crt] => GAS 
     [operatori] => data 
     [data] => 2015-12-24 
     [status] => Atessa 
     [nome] => dscc 
     [cognome] => csdfvsg 
     [cel] => wgwegwe 
     [codice_fiscale] => rgrwgrwg 
    ) 

[18] => Array 
    (
     [supervizori] => data 
     [grupi] => Bosat //this is the team 
     [tipo_crt] => data 
     [operatori] => data 
     [data] => 2015-12-24 
     [status] => OK 
     [nome] => dscc 
     [cognome] => csdfvsg 
     [cel] => wgwegwe 
     [codice_fiscale] => rgrwgrwg 
    ) 

[19] => Array 
    (
     [supervizori] => data 
     [grupi] => Doctors //this is the team 
     [tipo_crt] => LUCE 
     [operatori] => data 
     [data] => 2015-12-29 
     [status] => Atessa 
     [nome] => dhr 
     [cognome] => rhrdh 
     [cel] => rdhrdh 
     [codice_fiscale] => rdhrdh 
    ) 

[20] => Array 
    (
     [supervizori] => data 
     [grupi] => Doctors //this is the team 
     [tipo_crt] => LUCE 
     [operatori] => data 
     [data] => 2016-01-04 
     [status] => OK 
     [nome] => dwadwa 
     [cognome] => jgv 
     [cel] => jlgv 
     [codice_fiscale] => jgv 
    ) // this is the first array from orders 

Array 
(
    [8] => Array 
     (
      [grup_name] => BMW 
     ) 

    [9] => Array 
     (
      [grup_name] => Doctors  
     ) 

    [10] => Array 
     (
      [grup_name] => Bosat  
     ) 

)// the teams array 

Answer 1

這應該做的工作：根據您的需求

$completeData = array(); 

foreach($orders as $order) 
{ 
    if(!array_key_exists($order['grupi'], $completeData)) 
    { 
     $completeData[$order['grupi']] = array(); 
    } 
    $completeData[$order['grupi']][] = $order; 
} 

調。