php和mysql到xml

Question

我有兩個表，第一個存儲餐廳信息和第二個商店的菜餚在每個服務。它們使用res_id鏈接。

1）info_main [ID，RES_ID，RES_NAME，res_pc] 2）菜[ID，dishName，價格，RES_ID（外鍵）

我的SQL查詢

$query = "SELECT * FROM info_main LEFT JOIN dishes ON info_main.res_id = dishes.res_id"; 

我將查詢結果插入一個可以正常工作的xml文件中。下面是代碼：

這項工作很好但是如果餐廳有3個菜在數據庫中，然後XML創建3個節點：事情是這樣的：

我想要的XML結構像

<detail1> 
<resdetails name="spoted dog" id="xyz" pc="xyz"/> 
<dishdetails name="bean burger" price="1" /> 
<dishdetails name="cheese and tomato panini" price="3" /> 
<dishdetails name="veg salad" price="2" /> 
</details1> 

我不知道如何實現上述XML結構的方式。非常感謝您的幫助。由於

Answer 1

Atlast我得到了那個工作，我用了兩個查詢，一個得到不同的restarant和其他獲得菜名。我在主循環中使用循環。下面是代碼。

$query = "SELECT DISTINCT * FROM info_main"; 

$result = mysql_query($query); 


if (!$result) { 
    die('Invalid query: ' . mysql_error()); 
} 
header("Content-type: text/xml"); 

echo '<markers>'; 

// Iterate through the rows, printing XML nodes for each 
while ($row = @mysql_fetch_assoc($result)){ 
    $id=$row['res_id']; 
    // ADD TO XML DOCUMENT NODE 
    echo '<marker> '; 

     echo '<detail1>'; 
     echo '<resdetails '; 
      echo 'name="' . parseToXML($row['res_name']) . '" '; 
      echo 'id="' . parseToXML($id) . '" '; 
      echo 'pc="' . parseToXML($row['res_pc']). '" '; 
     echo '/>'; 

     $dishes = "SELECT * FROM dishes WHERE res_id = '" . $id . "'"; 

     $dish = mysql_query($dishes); 

     while ($row2 = @mysql_fetch_assoc($dish)){ 
      $id2 = $row2['res_id']; 

      echo '<dishdetails '; 
       echo 'name="' . parseToXML($row2['dishName']) . '" '; 
       echo 'price="' . parseToXML($row2['price']) . '" '; 
      echo '/>'; 

     } 

     echo '</detail1>'; 

     echo '</marker>'; 
    } 
echo '</markers>'; 

Answer 2

$query = "SELECT * FROM info_main LEFT JOIN dishes ON info_main.res_id = dishes.res_id"; 
$result = mysql_query($query); 

if (!$result) { 
    die('Invalid query: ' . mysql_error()); 
} 
header("Content-type: text/xml"); 

echo '<markers>'; 

// Iterate through the rows, printing XML nodes for each 
$resname = ""; 
while ($row = @mysql_fetch_assoc($result)){ 
    // ADD TO XML DOCUMENT NODE 
    if ($resname!=$row['res_name']) { 
    //restname isn't populated or doesn't match current so output new headers 
    echo '<marker> '; 
     echo '<detail1>'; 
     echo '<resdetails '; 
      echo 'name="' . parseToXML($row['res_name']) . '" '; 
      echo 'id="' . parseToXML($row['res_ID']) . '" '; 
      echo 'pc="' . parseToXML($row['res_pc']). '" '; 
     echo '/>'; 
    } 
     //this bit needs to always happen 
     echo '<dishdetails '; 
      echo 'name="' . parseToXML($row['dishName']) . '" '; 
      echo 'price="' . parseToXML($row['price']) . '" '; 
     echo '/>'; 


    if ($resname!=$row['res_name']) { 
    //restname isn't populated or doesn't match current so output new headers 
     echo '</detail1>'; 

     echo '</marker>'; 
    } 
    $resname = $row['res_name']; //set resname to this res_name as this is our check to see if we've already put out required headers for this item that way every change it'll put this back in 
    } 

像這樣的東西（注可能需要一些整理）

Answer 3

對於結構只是這樣做：

echo '<marker> '; 

    echo '<detail1>'; 

while ($row = @mysql_fetch_assoc($result)){ 

echo '<dishdetails '; 
     echo 'name="' . parseToXML($row['dishName']) . '" '; 
     echo 'price="' . parseToXML($row['price']) . '" '; 
    echo '/>'; 

} 

echo '</detail1>'; 

    echo '</marker>'; 

所有這一切真的是不同的，是讓我感動的一部分你的代碼不在while循環中。