如何正確返回？

Question

我無法正確地返回答案。

return roll_dice(x)的語法是否正確，或者是否需要用括號中的其他內容替換x？

我是初學者，想一些幫助，這個問題：

我的代碼：

import numpy as np 

def roll_dice(x): 
    totmoney = 0 

    for a in range(x): 
     throw_one = np.random.randint(6) 
     throw_two = np.random.randint(6) 

     if throw_one % 2 != 0 or throw_two % 2 != 0: 
      totmoney += throw_one + throw_two 
      print throw_one,"|",throw_two,"|",totmoney 
     else: 
      totmoney -= throw_one + throw_two 
      print throw_one,"|",throw_two,"|",totmoney 

     return roll_dice(x) 

Answer 1

無需做太多的修改，我覺得你想要做的是：

import random 

def roll_dice(x): 
    totmoney = 0 
    result_matrix = [] 

    for a in range(x): 
     throw_one = random.randint(1, 6) 
     throw_two = random.randint(1, 6) 

     if throw_one % 2 != 0 or throw_two % 2 != 0: 
      totmoney += throw_one + throw_two 
      print throw_one,"|",throw_two,"|",totmoney 
     else: 
      totmoney -= throw_one + throw_two 
      print throw_one,"|",throw_two,"|",totmoney 

     result_matrix.append([throw_one, throw_two, totmoney]) 

    return result_matrix 

example = roll_dice(2) 
print example 

（我使用了random模塊，因爲我沒有安裝numpy）

每次通過循環時，都會一次創建一行矩陣，最後這個矩陣就是您返回的內容。

但我會增加一些額外的修改：

import random 

def roll_dice(x): 
    totmoney = 0 
    result_matrix = [] 

    for a in range(x): 
     throws = [random.randint(1, 6), random.randint(1, 6)] 

     if throws[0] % 2 != 0 or throws[1] % 2 != 0: 
      totmoney += sum(throws) 
     else: 
      totmoney -= sum(throws) 

     print throws[0],"|",throws[1],"|",totmoney 

     result_matrix.append([throws[0], throws[1], totmoney]) 

    return result_matrix 

example = roll_dice(2) 
print example 

這是我已經到位：

• 我已經把你的兩個投到命名列表throws
• 我已經使用sum函數添加這兩個拋出
• 我已經把你的print聲明放在你的if聲明

我們可以走得更遠，但我越來越疲憊，我不想把你和更先進的東西混淆。