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我正在使用HTML5構建一個簡單的錄製應用程序,我試圖將文件分成較小的位並將每一位保存到Web服務器以模擬實時流?我已經得到了記錄和分割的代碼,但由於某種原因,只有第一個切片會被記錄下來。其餘的都是有數據,但不會玩(至少不能在VLC)如何使用recorder.js,getUserMedia和blob.slice正確切分音頻文件?
下面是代碼:
window.URL = window.URL || window.webkitURL;
navigator.getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia || navigator.msGetUserMedia;
var audio = document.querySelector('audio');
var context = new webkitAudioContext();
var recorder;
var lastByte = 0;
var intv;
var fileCount = 1;
var onFail = function(e) {
document.getElementById("results").innerHTML = "An error Occured<br />" + e;
};
var onSuccess = function(s) {
var mediaStreamSource = context.createMediaStreamSource(s);
recorder = new Recorder(mediaStreamSource);
recorder.record();
intv = setInterval(function(){getSnippet();} , 3000);
}
function startRecording() {
if (navigator.getUserMedia) {
document.getElementById("results").innerHTML = "Starting....";
navigator.getUserMedia({audio: true}, onSuccess, onFail);
}
else {
document.getElementById("results").innerHTML = "Get User Media not Present/Active";
}
}
function stopRecording() {
recorder.stop();
clearInterval(intv);
recorder.exportWAV(function(s) { console.log(s);
saveSnippet(s, "Final");
audio.src = window.URL.createObjectURL(s);
});
}
function getSnippet(){
recorder.exportWAV(function(s) {
//Slice the unsaved part of the file
slc = s.slice(lastByte, s.size, s.type);
console.log("Start: " + lastByte + "; End: " + s.size + "; FileName: " + fileCount);
saveSnippet(slc, fileCount);
lastByte = s.size;
fileCount++;
});
//recorder.exportWAV(function(s) { saveFile(s); });
}
function saveSnippet(s, fname){
var fd = new FormData();
fd.append('fname', fname + '.wav');
fd.append('fileToUpload', s);
$.ajax({
url: 'savefile.php',
type: 'POST',
data: fd,
processData: false,
contentType: false,
success: function(data){ document.getElementById("results").innerHTML = "File Saved: <br />" + data;},
error: function(jqXHR, textStatus, errorMessage) { document.getElementById("results").innerHTML = errorMessage; }
});
}
有什麼,我做錯了什麼,爲什麼會第一個文件記錄,但沒有後續文件? 我是一個完整的新手,所以請溫柔。如果有更好的方法來做到這一點,我就是耳朵!
如這裏要求是爲savefile.php
if(count($_FILES) > 0){
echo "Data Found<br />";
echo $_FILES['fileToUpload']['tmp_name'];
$fl = file_get_contents($_FILES['fileToUpload']['tmp_name']);
echo "<br />File Uploaded: " . file_put_contents("uploads/" . $_POST['fname'], $fl, FILE_APPEND);
}
你能張貼'savefile.php'代碼 - 我的猜測是,你要保存的同名 – user20232359723568423357842364
文件@ user20232359723568423357842364我更新了名稱每次我打電話的功能,所以我不認爲問題是命名文件相同的事情。另外,我正在上傳的文件夾中收到多個文件,其中包含多個文件。 – TemiGiwa