添加對象的內容而不是參數類型？

Question

希望我能夠正確，清楚地描述這一點。我正在嘗試保存用戶輸入的多個詳細信息並將其保存到列表中。然而目前我這樣做的方式只是保存對象類型/名稱而不是數據。下面是我的代碼，我將如何保存對象數據而不是對象的名稱？

Student stud = new Student(); 
stud.Enter_Student(); 
_studentList.Add(stud); 

從人級的輸入學生

class Student : Person 
{ 
    public string StudentId { get; private set; } 
    public string Subject { get; private set; } 

    //string[] _studentdb = new string[4]; 

    public Student() 
    { 
     StudentId = "abc123"; 
     Subject = "Building Subject"; 
    } 

    public void Enter_Student() 
    { 
      this.Person_Prompt_Print(); //Prompts for user 
      this.Address_Prompt_Print(); 
      this.Contact_Prompt_Print(); 
      Console.SetCursorPosition(4, 18); 
      Console.WriteLine("Student ID:"); 

      this.Enter_Person(); // Inputs from user 
      this.Enter_Address(); 
      this.Enter_Contacts(); 
      StudentId = Console.ReadLine(); 
      Console.SetCursorPosition(30, 18); 
    } 
} 

日期樣品

class Person 
{ 

    Tidyup tidy = new Tidyup(); 

    public string FirstName { get; private set; } 
    public string Surname { get; private set; } 
    public string MiddleName { get; private set; } 
    public string AddressLine1 { get; private set; } 
    public string AddressLine2 { get; private set; } 
    public string Town { get; private set; } 
    public string Postcode { get; private set; } 
    public string Email { get; private set; } 
    public string Telephone { get; private set; } 



    public Person() 
    { 
     FirstName = "Name"; 
     Surname = "Surname"; 
     MiddleName = "Middle Name"; 
     AddressLine1 = "Address"; 
     AddressLine2 = "Address Ln2"; 
     Town = "Town"; 
     Postcode = "<xxx>/<xxx>"; 
     Email = "name@buildright.ac.uk"; 
     Telephone = "0800 0000000"; 
    } 

    public void Person_Prompt_Print() 
    { 
     // Program Frame 
     tidy.Line_Top(); 
     tidy.Line_Base(); 
     tidy.Sides_Left(); 
     tidy.Sides_Right(); 

     Console.SetCursorPosition(4, 2); //Prompts for user 
     Console.WriteLine("FirstName:"); 
     Console.SetCursorPosition(4, 4); 
     Console.WriteLine("Surname:"); 
     Console.SetCursorPosition(4, 6); 
     Console.WriteLine("Middle Name:"); 
    } 

    public void Address_Prompt_Print() 
    { 
     Console.SetCursorPosition(4, 8); //Prompts for user 
     Console.WriteLine("House Number/Name:"); 
     Console.SetCursorPosition(4, 10); 
     Console.WriteLine("Street:"); 
     Console.SetCursorPosition(4, 12); 
     Console.WriteLine("Town:"); 
     Console.SetCursorPosition(4, 14); 
     Console.WriteLine("Post Code:"); 
    } 

    public void Contact_Prompt_Print() 
    { 
     Console.SetCursorPosition(4, 16); 
     Console.WriteLine("Email:"); 
     Console.SetCursorPosition(4, 18); 
     Console.WriteLine("Telephone:"); 
    } 

    public void Enter_Person() 
    { 

     Console.SetCursorPosition(30, 2); // Inputs from user 
     FirstName = Console.ReadLine(); 
     Console.SetCursorPosition(30, 4); 
     Surname = Console.ReadLine(); 
     Console.SetCursorPosition(30, 6); 
     MiddleName = Console.ReadLine(); 
    } 

    public void Enter_Address() 
    { 

     Console.SetCursorPosition(30, 8); // Inputs from user 
     AddressLine1 = Console.ReadLine(); 
     Console.SetCursorPosition(30, 10); 
     AddressLine2 = Console.ReadLine(); 
     Console.SetCursorPosition(30, 12); 
     Town = Console.ReadLine(); 
     Console.SetCursorPosition(30, 14); 
     Postcode = Console.ReadLine(); 
    } 

    public void Enter_Contacts() 
    { 
     Console.SetCursorPosition(30, 16); 
     Email = Console.ReadLine(); 
     Console.SetCursorPosition(30, 18); 
     Telephone = Console.ReadLine(); 
    } 

} // End of Class 

最後我通過一個簡單的嵌套foreach循環打印出

public void Print_all_student() 
{ 
    Console.Clear(); 

    foreach (Student t in _studentList) 
    { 
     // print another list items. 
     foreach (Student t1 in _studentList) 
     { 
      Console.WriteLine("/" + t + "/" + t1); 
     } 
    } 
    Console.ReadKey(); 
} 

如果任何人都可以幫助我瞭解什麼我錯過了，以及如何訪問數據打印出來，我將不勝感激。預先感謝您提供的任何幫助。

Answer 1

有很多的問題在這裏，但在你的Console.WriteLine電話，你只顯示Student類型，所以在Student類型ToString方法將被調用，默認情況下將顯示類型名稱。

您想要顯示Student類型的各個屬性，例如，

foreach (Student student in studentList) 
{ 
    Console.WriteLine(student.FirstName); 
    Console.WriteLine(student.Surname); 
    // etc 
} 

記住Student從Person派生，因此，所有的公共屬性都從Student參考訪問，因爲Student是Person。

另外：

1. 你有一個冗餘環路 - 你只需要一個循環，其列舉了studentList
2. 還有就是這裏的擔憂真正的混合物。你Student和Person類型不應與UI（即任何與Console電話）
3. 棒與PascalCase（又名UpperCamelCase）爲您的方法名，沒有強調