包含在多個.cpp文件中的頭文件

Question

我遵循了一個簡單的例子，如下所示。但編譯失敗。

請你看看，給我一些建議。

vs2010控制檯應用程序used.Thank你。

錯誤消息

pgm.h(11): error C4430: missing type specifier - int assumed. Note: C++ does not support default-int 
pgm.h(11): error C2143: syntax error : missing ',' before '&' 
1> multi_fct.cpp 
pgm.h(11): error C4430: missing type specifier - int assumed. Note: C++ does not support default-int 
pgm.h(11): error C2143: syntax error : missing ',' before '&' 
1> ch3_p96.cpp 
pgm.h(11): error C4430: missing type specifier - int assumed. Note: C++ does not support default-int 
pgm.h(11): error C2143: syntax error : missing ',' before '&' 
ch3_p96.cpp(24): error C2664: 'prn_info' : cannot convert parameter 1 from 'const char [8]' to 'const int' 
1>   There is no context in which this conversion is possible 
ch3_p96.cpp(26): error C3861: 'fct1': identifier not found 

pgm.h

#include <iostream> 
#include <cstdlib> 
#include <string> 

#define  N 3 

void fctl(int k); 
void fct2(); 
void prn_info(const string& pgm_name); 

ch3_p96.cpp

#include "stdafx.h" 

#include <iostream> 

#include "pgm.h" 

using namespace std; 

int main() 
{ 
    char ans; 
    int k, n = N; 

    cout << "This program does not do very much.\n"; 
    cout << "Do you want more information?\n"; 
    cout << "Enter either y or Y is yes.\n" << endl; 

    cin >> ans; 

    if (ans == 'y' || ans == 'Y') 
     prn_info("ch3_p96"); // multi_main 
    for (k = 0; k < n; ++k) 
     fct1(k); 

    cout << "Best Regards!" << endl; 

} 

multi_fct.cpp

#include "StdAfx.h" 

#include <iostream> 
#include "pgm.h" 

using namespace std; 

void fct1(int n) 
{ 
    int i; 

    cout << "Hello from fct1()" << endl; 
    for (i = 0; i < n; ++i) 
     fct2(); 
} 

void fct2() 
{ 
    cout << "Hello from fct2()" << endl; 

} 

multi_prn.cpp

#include "StdAfx.h" 

#include <iostream> 
#include <string> 
#include "pgm.h" 

using namespace std; 

void prn_info(const string& pgm_name) 
{ 
    cout << "Usage: " << pgm_name << endl; 
    cout << "This program illustrates a " << endl; 
    cout << "Program is more than one file. " << endl; 
    cout << "In this example, a single" << endl; 
    cout << ".h file is included at the" << endl; 
    cout << "top of our three .cpp files." << endl; 
    cout << "Thus pgm.h acts as the \"glue\"" << endl; 
    cout << "that binds the program." << endl; 
} 

Answer 1

您需要命名空間限定的字符串：std::string。

編譯器錯誤是說它沒有找到類型名稱，所以它猜測string是int，並繼續嘗試和解析您的代碼。

此外，在一個地方，您使用fctl（fct lower-case-L）並在一個地方使用fct1（fct one）。

Answer 2

需要判定字符串：

void prn_info(const std::string& pgm_name); 

它在std命名空間。請不要在頭文件中使用using namespace std。