SQL查詢來獲得單值組合多個ID，通過逗號分隔

Question

我有2個表Employee and Skills具有以下字段：

員工：Id,Name,Location

技能：Id,Skills

Employee數據：

Id Name Location 
7  Abc  London 
8  Xyz  London 
9  Xyz  USA 
10 Abc  USA 

技能：

Id skills  EmployeeId 
12 AAA Xyz  7 
13 BBB   7 
14 CCC   7 
15 AAA   8 
16 BBB   8 
17 CCC   8 
18 AAA   9 
19 BBB   9 
20 CCC   9 
21 AAA   10 
22 BBB   10 
20 CCC   10 

現在我想技能的僱員的Name is Abc的，Location is London and Skills is both AAA and BBB只有，但我想單輸出象下面這樣：

Skills 
10,11 

這是我的查詢：

select S.Id from Employee E inner join 
Skills S on E.Id=s.EmployeeId 
where (E.Name='Abc' and E.Location='London' 
and s.skills='AAA') and (E.Name='Abc' and E.Location='London' 
and s.skills='BBB') 

但輸出錯誤。

任何人都可以幫助我嗎？

Answer 1

您可以使用STUFF這個：

Select Stuff 
(
    (
     Select ',' + Convert(Varchar, S.Id) 
     From Employee E 
     Join Skills  S On S.EmployeeId = E.Id 
     Where E.Name = 'Abc' 
     And  E.Location = 'London' 
     And  S.Skills In ('AAA', 'BBB') 
     For Xml Path ('') 
    ), 1, 1, '' 
) As Skills 

編輯：SQL小提琴似乎不想在此刻和我一起工作，但使用下面的數據（從OP），它得到的正確的結果：

Create Table Skills 
(
    Id int, 
    skills varchar (3), 
    employeeid int 
); 

Create Table Employee 
(
    Id int, 
    Name varchar (10), 
    location varchar (10) 
); 

insert skills values 
(10 ,'AAA',  1), 
(11 ,'BBB',  1), 
(13 ,'CCC',  1), 
(14 ,'DDD',  1); 

insert employee values 
( 1  ,'Abc' , 'London'), 
( 2  ,'Xyz',  'Uk'); 


Select Stuff 
(
    (
     Select ',' + Convert(Varchar, S.Id) 
     From Employee E 
     Join Skills  S On S.EmployeeId = E.Id 
     Where E.Name = 'Abc' 
     And  E.Location = 'London' 
     And  S.Skills In ('AAA', 'BBB') 
     For Xml Path ('') 
    ), 1, 1, '' 
) As Skills 

編輯＃2新數據;相同的查詢：

Create Table Skills 
(
    Id int, 
    skills varchar (3), 
    employeeid int 
); 

Create Table Employee 
(
    Id int, 
    Name varchar (10), 
    location varchar (10) 
); 

insert skills values 
(12 ,'AAA',  7 ), 
(13 ,'BBB',  7 ), 
(14 ,'CCC',  7 ), 
(15 ,'AAA',  8 ), 
(16 ,'BBB',  8 ), 
(17 ,'CCC',  8 ), 
(18 ,'AAA',  9 ), 
(19 ,'BBB',  9 ), 
(20 ,'CCC',  9 ), 
(21 ,'AAA',  10 ), 
(22 ,'BBB',  10 ), 
(20 ,'CCC',  10 ); 

insert employee values 
(7  ,'Abc',  'London' ), 
(8  ,'Xyz',  'London' ), 
(9  ,'Xyz',  'USA'  ), 
(10 ,'Abc',  'USA'  ); 


Select Stuff 
(
    (
     Select ',' + Convert(Varchar, S.Id) 
     From Employee E 
     Join Skills  S On S.EmployeeId = E.Id 
     Where E.Name = 'Abc' 
     And  E.Location = 'London' 
     And  S.Skills In ('AAA', 'BBB') 
     For Xml Path ('') 
    ), 1, 1, '' 
) As Skills 

，結果這次是12,13 - 根據您的條件，這是正確的：

員工7是唯一一個與Abc從London，並12和13是技能AAA和BBB。