拆分查詢結果劃分爲有自己的表，根據相同的ID

Question

我使用當前顯示的全部結果的表如下：

$result = mysqli_query($con,"SELECT * FROM b_tasks_po"); 

while($row = mysqli_fetch_array($result)) 

{ 
echo "<tr>"; 
echo "<td class='tdclass' width='100'>" . $row['TASK_ID'] . "</td>"; 
echo "<td class='tdclass' width='100'>" . $row['QTY'] . "</td>"; 
echo "<td class='tdclass' width='100'>" . $row['CODE'] . "</td>"; 
echo "<td class='tdclass' width='500'>" . $row['PRODUCT_DESCRIPTION'] . "</td>"; 
echo "</tr>"; 
}     
?> 

</table> 

這帶來了以下內容：

| Task ID | Qty | Code | Description 
| 1  | 200 | AB1 | Frame 1 
| 1  | 350 | AB2 | Frame 2 
| 2  | 100 | AB3 | Frame 3 
| 2  | 120 | AB4 | Frame 4 
| 2  | 300 | AB5 | Frame 5 

這裏是我的想要，我不知道我該怎麼做。我需要爲每組ID創建一個新表。因此，例如：

TABLE ONE 

| Task ID | Qty | Code | Description 
| 1  | 200 | AB1 | Frame 1 
| 1  | 350 | AB2 | Frame 2 

TABLE TWO 

| Task ID | Qty | Code | Description 
| 2  | 100 | AB3 | Frame 3 
| 2  | 120 | AB4 | Frame 4 
| 2  | 300 | AB5 | Frame 5 

我想到了分組由TASK_ID的結果，但沒有喜悅和我也想過用if語句，但不能爲我的生活工作如何做到這一點。

任何幫助，將不勝感激。

Answer 1

您需要對task_id更改時的結果進行排序並重新打印標題。例如：

<? 
$result = mysqli_query($con,"SELECT * FROM b_tasks_po ORDER BY TASK_ID"); 

$current_task_id = -1; 
while($row = mysqli_fetch_array($result)) 
{ 
    if($current_task_id != $row['TASK_ID']) 
    { 
     echo "</table><table>"; 
     echo "<tr>"; 
     echo "<th width='100'>Task ID</th>"; 
     echo "<th width='100'>Qty</th>"; 
     echo "<th width='100'>Code</th>"; 
     echo "<th width='500'>Description</th>"; 
     echo "</tr>"; 
     $current_task_id = $row['TASK_ID']; 
    } 
    echo "<tr>"; 
    echo "<td class='tdclass' width='100'>" . $row['TASK_ID'] . "</td>"; 
    echo "<td class='tdclass' width='100'>" . $row['QTY'] . "</td>"; 
    echo "<td class='tdclass' width='100'>" . $row['CODE'] . "</td>"; 
    echo "<td class='tdclass' width='500'>" . $row['PRODUCT_DESCRIPTION'] . "</td>"; 
    echo "</tr>"; 
} 

?> 

</table>